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yulyashka [42]
3 years ago
9

a traditional square bale of hay is actually in the shape of a rectangular prism. it's dimensions are 2 feet by 2 feet by 4 feet

l. how many square bales contain the same amount of hay as one large round bale?
Mathematics
1 answer:
miskamm [114]3 years ago
8 0
First calculate the volume of the square bale, in the shae of a rectangular prism. using the formula:
V = l x w x h
where l is the length
w is the width
h is the height

V = 2 x 2 x 4
V = 16 sq ft.
then divide is by the volume of the total volume of hay
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3 years ago
Hi what isthe answer
REY [17]

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2x^7

Step-by-step explanation:

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8 0
3 years ago
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
4 years ago
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Irina-Kira [14]

Answer:

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To solve this equation, we need to isolate x on one side of the equation algebraically. I see that we have like terms, but they are on opposite sides of the equal sign. Let's add 6 to both sides.

21=7x

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7 0
3 years ago
FIND om if LO bisects
disa [49]
First you use Pythagorean theorem to find LO is square root of 194(13^2 + 5^2)=13.9. Then use the same method to find OM (194+13^2=363, square root of 363 is 19.1) and get that OM is 19.1
7 0
3 years ago
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