So the equation is t-2 ≥ t-8 which also equals t ≥ t-10 id ont know if this help but what are you trying to find
Answer:
(-4,2)
Step-by-step explanation:
By definition of tangent,
tan(<em>x</em>) = sin(<em>x</em>) / cos(<em>x</em>)
so if tan(<em>x</em>) < 0, and we're given cos(<em>x</em>) = -1/4 < 0, then it follows that sin(<em>x</em>) > 0.
Recall the Pythagorean identity:
cos²(<em>x</em>) + sin²(<em>x</em>) = 1 → sin(<em>x</em>) = + √(1 - cos²(<em>x</em>))
Then
sin(<em>x</em>) = √(1 - (-1/4)²) = √(15/16) = √(15)/4
Recall the double angle identity:
sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)
Then
sin(2<em>x</em>) = 2 • √(15)/4 • (-1/4) = -2√(15)/16 = -√(15)/8
1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer:
Step-by-step explanation:
find the square root of 5/3 then take that number and do the pathagerian therom
