Help me plz the first number if four

Scientists use supporting evidence to create an explanation. Explain why using evidence to support your explanations is a good p

lesya [120]

Answer: Scientific inquiry refers to the diverse ways in which scientists study the natural world and propose explanations based on the evidence derived from their work. Inquiry also refers to the activities of students in which they develop knowledge and understanding of scientific ideas, as well as an understanding of how scientists study the natural world. National Science Education Standards, p. 23.

As pointed out in the National Science Education Standards (National Research Council, 1996), students who use inquiry to learn science engage in many of the same activities and thinking processes as scientists who are seeking to expand human knowledge of the natural world. Yet the activities and thinking processes used by scientists are not always familiar to the educator seeking to introduce inquiry into the classroom. By describing inquiry in both science and in classrooms, this volume explores the many facets of inquiry in science education. Through examples and discussion, it shows how students and teachers can use inquiry to learn how to do science, learn about the nature of science, and learn science content.

A good way to begin this investigation is to compare the methods and thinking process of a practicing scientist with the activities of an inquiry-based science lesson. The stories in this chapter set the stage for many of the themes to follow. The sidebars suggest some important aspects of the investigations of both scientists and students.

INQUIRY IN SCIENCE

A geologist who was mapping coastal deposits in the state of Washington was surprised to discover a forest of dead cedar trees near the shore. A significant portion were still standing, but they clearly had been dead for many years. He found similar

3 0

3 years ago

Sarafina is making monthly payments into an annuity. She wants to have $800 in fund to buy a new convection range in three month

victus00 [196]

Answer:

$265.07

Step-by-step explanation:

The formula for the future value of an annuity is applicable.

A = P((1+r)^n-1)/r . . . . where r is the monthly interest rate and n is the number of months. P is the monthly payment, and A is the amount of the future value.

800 = P(1.006^3 -1)/(.006) = 3.018036P

P = 800/3.018036 ≈ 265.07

Sarafina's monthly payments need to be $265.07.

_____

This is about $1.60 less than the 266.67 she would deposit if she simply divided the desired balance by the number of months.

Because this number is rounded down, Sarafina will have a balance after 3 months of $799.99.

6 0

4 years ago

Jayla has been doing sit-ups to get in shape. She created a stem and leaf chart that displays the number of sit-ups she has alre

Rashid [163]

Answer:

hi how are you Ken foing tour homework

7 0

3 years ago

How do you solve the following equation: 5-(2x-3)=-8+2x

kirza4 [7]

I believe it would be done like this:
subtract 2x-8 from both sides. then use cubric formula.
answer should be x= 1.688242

4 0

4 years ago

Obtain or compute the following quantities.

iVinArrow [24]

Answer:

a) $F_{0.05,4,7}=0.16$

b) $F_{0.05,7,4}=0.24$

c) $F_{0.95,4,7}=4.12$

d) $F_{0.95,7,4}=6.09$

e) $F_{0.99,8,12}=4.50$

f) $F_{0.01,8,12}=0.18$

g) $P(F_{5,4} \leq 6.26)=0.95$

h) $P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

$F_{0.05,4,7}=0.16$

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

$F_{0.05,7,4}=0.24$

(c) F0.95, 4, 7 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

$F_{0.95,4,7}=4.12$

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

$F_{0.95,7,4}=6.09$

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

$F_{0.99,8,12}=4.50$

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

$F_{0.01,8,12}=0.18$

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

$P(F_{5,4} \leq 6.26)=0.95$

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

$P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

3 0

3 years ago

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