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lesya692 [45]
3 years ago
10

Which rectangular prism has a surface area of 56 square units? [Note: Art is not drawn to scale.]

Mathematics
1 answer:
Julli [10]3 years ago
3 0
Do u know how to solve area
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The circumference would be 53.38 because the formula on finding the circumference is pi times the diameter.
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On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0
3 years ago
4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
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Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

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2 years ago
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D will form a triangle


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