a minivan can hold up to 7 people. How many minivans are needed to take 45 people to a basketball game?

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

$IQR= Q_3 -Q_1$

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0

3 years ago

Find the 44th percentile, P44, from the following data! pls help

irina [24]

Answer:

$P_{44} = 29.9$

Step-by-step Explanation:

The 44th percentile, $P_{44}$ , of the given data can be calculated using the kth formula for percentile given as:

$i = \frac{k}{100}(n + 1)$

where,

i = the ranking or the position of the percentile = ?

k = the percentile = 44

n = total number of the given data values = 23

Plug in the values into the formula to find "i"

$i = \frac{44}{100}(23 + 1)$

$i = \frac{44}{100}(24)$

$i = \frac{1,056}{100}$

$i = 10.56$

Since "I", 10.56, is not an integer, round the number down, and round it up to the nearest integer, then look for the position each occupy in the ordered data set, and find their average.

Thus,

$i_{down} = 10.56 = 10$

$i_{up} = 10.56 = 11$

The data occupying the 10th position on the data set = 28.7

11th = 31.1

$P_{44} = \frac{28.7 + 31.1}{2} = \frac{59.8}{2}$

$P_{44} = 29.9$

6 0

3 years ago