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barxatty [35]
3 years ago
9

a shopkeeper mixed 15.25 kg of hazelnuts with 4.75 kg of raisins. He packed the mixture equally into 5 boxes. What is the weight

of each box?​
Mathematics
2 answers:
kaheart [24]3 years ago
5 0

Answer:

4 kgs

thats the sum by 5

hope it helps

BaLLatris [955]3 years ago
3 0

Answer:

<u>4kg</u>

15.25 + 4.75 = 20

20/5 = 4

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Which of these tables represents a linear function?
IrinaK [193]

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The second table because they are almost the same thing

Step-by-step explanation:

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2 years ago
Solve the equation -7 = y for x.
Harlamova29_29 [7]

Answer:

x = 4y+28

Step-by-step explanation:

x/4 -7 = y

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5 0
3 years ago
Read 2 more answers
Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.
borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 14, p = 0.8

P(x>10)

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501

P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501

P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539

P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981

So P(x > 10) = 0.6981.

8 0
3 years ago
Can you conclude with a high degree of confidence that the population means for Iowa and New Jersey students are​ different? A.
Katen [24]

Complete Question

The complete question is  shown on the first uploaded image

Answer:

Option A is correct

Step-by-step explanation:

From the question we are told that  

  The  95% confidence interval of the mean  score of all  New Jersey third graders  is  (58.957 ,  63.043)

   The sample size is  n =  184

   The sample average is  \mu = 65 \ points

   The standard deviation is   \sigma  =  13 \ points

    The  90%  confidence interval for the difference in mean score between lowa and New Jersey is  (-6.33 ,  -1.67 )

   The  p-value is  p-value  =  0.0048

Generally given that the p-values is very low compared to the level of significance (100 -90 =  10% = 0.10 )  we can reject the null hypothesis which is usually a  claim that the means of the  population are the same )

Hence the population means are different .

6 0
3 years ago
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