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barxatty [35]
3 years ago
9

a shopkeeper mixed 15.25 kg of hazelnuts with 4.75 kg of raisins. He packed the mixture equally into 5 boxes. What is the weight

of each box?​
Mathematics
2 answers:
kaheart [24]3 years ago
5 0

Answer:

4 kgs

thats the sum by 5

hope it helps

BaLLatris [955]3 years ago
3 0

Answer:

<u>4kg</u>

15.25 + 4.75 = 20

20/5 = 4

Step-by-step explanation:

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inysia [295]

Answer: C) 133

Step-by-step explanation:

The formula to find the sample size is given by :-

n=(\dfrac{z^*\cdot\sigma}{E})^2

, where z* = Critical z-value

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E= Margin of error.

As per given , we have

\sigma=$35

E= 5

The critical z-value for 90% confidence level is 1.645.

Substitute al;l the value sin the above formula  , we get

n=(\dfrac{1.645\times 35}{5})^2

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n=132.595225\approx133

Hence, the minimum sample size needed is 133.

Thus , the correct answer is : C) 133

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