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MrMuchimi
3 years ago
9

Please help will reward brainly

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0
I think the answer would be 1. 
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Tristan is comparing two number patterns based on the information below. Both patterns start with the number 1. Pattern A follow
Oksana_A [137]

Answer:

  Pattern B gets larger faster.

Step-by-step explanation:

Pattern A: 1, 4, 7, 10, 13

Pattern B: 1, 5, 9, 13, 17

The terms of pattern B are larger than those of Pattern A by 1 less than the number of the term. (Term 5 of Pattern B is 4 more than term 5 of Pattern A, for example.)

4 0
3 years ago
Mr. Moran chose 10 different test scores out of 50, and they are shown below. For the following set of data, find the mean test
frozen [14]

Answer:

39.5

Step-by-step explanation:

5 0
3 years ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
3 years ago
What's 1/6 divided by 3
erma4kov [3.2K]

Answer:

1/18

Step-by-step explanation:

1/6 * 1/3

1 *1 = 1

6 * 3 = 18

1/18

5 0
3 years ago
Read 2 more answers
PLEASEEEEEE HELPPPPPPPP
Natali5045456 [20]
The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
8 0
3 years ago
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