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Anarel [89]
3 years ago
6

Using your calculator, find the proportion of observations from a standard normal distribution that satisfies the following stat

ement. Sketch the normal curve and shade the area under the curve that is the answer to the question: Z < –1.5.
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0
<span>Look at your table for a Z value of 1.55. The numbers on the far left column are your z values. See the 1.5 row, then move over to the 0.05 column to make it 1.55.
You'll see 0.9394.
That's the area under the normal curve from 1.55 to negative infinity.
But you wanted the area under the curve greater than 1.55.
Take 1-0.9394=0.0606.
You subtract from 1 because you know that the area under the whole curve is 1, so it gives you the area you need.</span>
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H^-2g for h=3 and g=27
Alexeev081 [22]
Plug h = 3 and g = 27 into the expression:

h^{-2}g=  \dfrac{g}{h^2} = \dfrac{27}{3^2} = \dfrac{27}{9} = 3
3 0
3 years ago
Angelica and genesis are trying to find the difference of 7-(-5). Genesis thinks the difference is -12. Angelica thinks the diff
Elena-2011 [213]

Answer:

12

Step-by-step explanation:

7-(-5) = 7+5

7+5 = 12

7-(-5) = 12

5 0
3 years ago
1) What can u do to get 2x alone on the left side?
CaHeK987 [17]

Answer:

1)

82.5 - <u>8</u><u>2</u><u>.</u><u>5</u> + 2x = 338.5 - <u>8</u><u>2</u><u>.</u><u>5</u>

<u>2</u>x = <u>2</u><u>5</u><u>6</u>

2)

2x ÷ <u>2</u> = 256 ÷ <u>2</u>

x = <u>1</u><u>2</u><u>8</u>

Step-by-step explanation:

1)

In order to get rid 82.5, you have to substract the same value on both side to get a 0 value.

2)

In order to find the value of x, you have to divide the value that is sticked with x which is 2. As you divide 2 by 2, you will get 1 as a single value of x so you have to divide 2 to both side too.

5 0
3 years ago
Complete the Domain and Range worksheet attached. You can type the answer into submit
VMariaS [17]
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3 years ago
Line parallel to y=-3x 4 and goes through (-4,6)
Eduardwww [97]
Y=-3x+4
Gradient, m= -3
Parallel lines have equal gradients;
So, equation II,
y=mx+c
y=-3x+c
Replacing for x and y using point (-4, 6)
6=-3(-4)+c
6=12+c
6-12=c
c=-6
y=-3x-6
7 0
3 years ago
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