The total number of coins is 9. Therefore
p+n+d = 9 (1)
There are two fewer nickels than dimes. Therefore
n = d - 2 (2)
From (1) and (2), obtain
p+(d-2)+d = 9
p + 2d = 11
p = 11 - 2d (3)
Total value:
0.01p + 0.05n + 0.10d = 0.53 (4)
Substitute (2) and (3) into (4).
0.01(11-2d) + 0.05(d-2) + 0.10d = 0.53
0.11 - 0.02d + 0.05d - 0.10 + 0.10d = 0.53
0.03d + 0.01 = 0.53
0.13d = 0.52
d = 4
p = 11 - 2d = 11 - 8 = 3
Answer: 3 pennies
Answer:
HG = 28
Step-by-step explanation:
The midsegment MN is half the sum of the 2 parallel bases, that is
= MN , that is
= 22 ( multiply both sides by 2 )
HG + 16 = 44 ( subtract 16 from both sides )
HG = 28
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Answer:
- equation: 10(-270 +n) = -20
- number: 268
Step-by-step explanation:
If n represents the number, we have ...
10(-270 +n) = -20 . . . an equation for n
__
The solution can be found as ...
-270 +n = -2 . . . . . divide by 10
n = 268 . . . . . . . add 270
The number is 268.
Answer:
the first one is b
the second one is c
Step-by-step explanation:
have a great day :D