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serg [7]
3 years ago
9

Information storage:Select one:a. Eliminates the need for professional judgment.b. Keeps data in a form accessible to informatio

n processors.c. Provides the basic information processed by an accounting system.d. Captures information from source documents.e. Includes all of these.
Computers and Technology
1 answer:
Vikentia [17]3 years ago
8 0

Answer:

B. Keeps data in a form accessible to information processors

Explanation:

Information storage is the part of the accounting system that keeps data accessible to the information processors. In other words, an accounting system’s information storage unit is either a hard drive or server that usually contains a database.

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Write an algorithm to calculate the average<br> value of array of integer elements
amid [387]

Answer:

Explanation: Input : arr[] = {1, 2, 3, 4, 5}

Output : 3

Sum of the elements is 1+2+3+4+5 = 15

and total number of elements is 5.

So average is 15/5 = 3

Input : arr[] = {5, 3, 6, 7, 5, 3}

Output : 4.83333

Sum of the elements is 5+3+6+7+5+3 = 29

and total number of elements is 6.

So average is 29/6 = 4.83333.

7 0
3 years ago
Write a program to input a number and check whether it is even or odd number
Mashutka [201]

Answer:#include <stdio.h>

int main() {

   int num;

   printf("Enter an integer: ");

   scanf("%d", &num);

   // true if num is perfectly divisible by 2

   if(num % 2 == 0)

       printf("%d is even.", num);

   else

       printf("%d is odd.", num);

   

   return 0;

}

3 0
3 years ago
For this assignment, you will write a program that calculates gross and net revenue for a movie theater. Consider the following
Marrrta [24]

Answer:

// This program is written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Declare variables

int childticket, adultticket, childprice, adultprice;

double total, net, distributor;

string movie;

// Prompt user for name of movie

cout<<"Movie Name; ";

// Accept input for movie name

cin>>movie;

// Prompt user and accept input for price of adult tickets

cout<<"Adult Ticket Price: $";

cin>>adultprice;

// Prompt user and accept input for price of child tickets

cout<<"Child Ticket Price: $";

cin>>childprice;

// Prompt user and accept input for number of sold adult tickets

cout<<"Adult Ticket Sold: ";

cin>>adultticket;

// Prompt user and accept input for number of child tickets sold

cout<<"Child Ticket Sold: ";

cin>>childticket;

// Calculate total

total = childticket * childprice + adultticket * adultprice;

// Calculate distributor's payment

distributor = 0.25 * total;

// Calculate net box pay

net = 0.75 * total;

// Display and format results

cout<<"Gross Box Office Revenue: $";

printf("%.2f",total);

cout<<"\n Amount Paid to Distributor: -$";

printf("%.2f", distributor);

cout<<"\nNet Box Office Revenue: $";

printf("%.2f",net);

return 0;

}

6 0
3 years ago
Any anime weebs wanna talk
erastova [34]

Answer:

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6 0
3 years ago
Read 2 more answers
How many bits can a memory chip with the below configuration support? For full credit, show how you got the answer.
tatiyna

Answer:

Total Memory= 4 KB = 4096 bytes = 32768 bits

Explanation:

<em><u>1. Data lines are 8 From D0 to D7</u></em>

so

Total memory at single address locations is 8 bits.

<em><u>2. Address lines are 12 (A0 to A11)</u></em>

There are 12 address lines but 3 out 12 are for selction of chip or memory bank.

so only 9 pins are there to address the locations on one chip.

Total No. of address locations on single chip = 2^9 = 512 locations

as 1 location is 1 byte so total memory of single chip is 512 bytes.

<u><em>3. Total Memory Bank </em></u>

There are total 3 selection pins for memory bank.

so

Total chips = 2^3 = 8.

<em><u>4. Total Memory </u></em>

Total size of 1 chip = 512 bytes

Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb

<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>

5 0
3 years ago
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