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Ilia_Sergeevich [38]
3 years ago
10

A fair 10 sided dice, with faces numbered 1-10, is rolled once. What is the probability that the number rolled will be prime? Ex

press your answer as a common fraction.
Mathematics
1 answer:
sp2606 [1]3 years ago
7 0
In numbers 1 through 10, there are 4 primes. So, the fraction would be:
\frac{4}{10}

This can be simplified to:
\frac{2}{5}

That's your answer!
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Solve for p<br> 3+|1+p|=12
Usimov [2.4K]
Subtract 3 from both sides

simplify 12 - 3 to 9

break down the problem into these two equations

1 + p = 9 and -(1 + p) = 9

solve the first equation 1 + p = 9 and that would be 8 since 1 + 8 = 9 is true.

solve the second equation -(1 + p) = 9 and just simplify brackets and add 1 to both sides then add 9 + 1 and lastly multiply both sides by -1 and p = -10.

Gather both solutions

Answers: p = -10, 8


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