Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so
3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w
3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2
2x+2x=4x
Answer:
13. B. 24 cm²
14. y = 5⅝ (none of the options is correct)
Step-by-step explanation:
13. The figure is a trapezoid
Area of the trapezoid = ½(a + b)h
Where,
a = 3 cm
b = 5 cm
h = 6 cm
Area = ½(3 + 5)6
= ½(8)6
= 4*6
= 24 cm²
14. Area of the triangle = ½*b*h
The area is given to be 45 cm²
base (b) = 16 cm
height (h) = y
Plug in the values and solve for y
45 = ½*16*y
45 = 8y
Divide both sides by 8
45/8 = 8y/8
45/8 = y
5⅝ = y
y = 5⅝ (none of the options is correct)
Set up a proprtion and cross multiply.
18/7.5=22/4x+1
7.5×22=18 (4x+1)
165=72x+18
147=72x
x=2.04
Answer:
6ft
Step-by-step explanation:
