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Mrrafil [7]
3 years ago
10

Fiona is serving iced tea and lemonade at a picnic. She has only 44 cups in which to serve the drinks. If x represents the numbe

r of glasses of iced tea and y represents the number of glasses of lemonade, which equation represents the number of glasses of iced tea she can serve?
Mathematics
2 answers:
il63 [147K]3 years ago
5 0

Answer:

x = 44 - y

Step-by-step explanation:

Given are the following information:

Number of cups that Fiona has for serving iced tea and lemonade =Total number of cups = 44

Number of glasses of iced tea served = x

Number of glasses of lemonade served = y

Then the equation can be represented by

x + y = 44\\x = 44 - y

pav-90 [236]3 years ago
3 0
Number of cups that Fiona has for serving iced tea and lemonade = 44
Number of glasses of iced tea served = x
Number of glasses of lemonade served = y
Then the equation can be represented by
x + y = 44
x = 44 - y
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Please solve, -8-2(7r+1)=-94​
skelet666 [1.2K]

Answer:

r = 6

Step-by-step explanation:

Hello!

-8 - 2(7r + 1) = -94

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3 years ago
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6.
larisa86 [58]

A. Every month Population will increase by a factor of 0.84%.

B.  Every 3 months Population will increase by a factor of 2.5%.

C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.

<u>Step-by-step explanation:</u>

Here, we have  number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as  x + \frac{x}{100}\times10 which is equivalent to \frac{11x}{10}.

<u>A.</u>

For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like \frac{10}{12}  = 0.84 . ∴ Every month Population will increase by a factor of 0.84%.

<u>B.</u>

In every 3 months: We have , 12 months in a year , in order to check for every 3 months  \frac{12}{3} = 4 and Now, Population increase in every 3 months is \frac{10}{4}  = 2.5.  ∴ Every 3 months Population will increase by a factor of 2.5%.

<u>C.</u>

In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.

So , increase in population in every 20 months is 10% + 6.72% = 16.72%.

5 0
3 years ago
Please help me please I reallly need help
kiruha [24]

Answer:

we have:

v  =  \frac{1}{3} \pi \: r {}^{2}h \\  \\  =  > 60\pi =  \frac{1}{3} \pi \: r {}^{2} h \\  \\  <  =  > 180 = r {}^{2} h

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12

3 0
3 years ago
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