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Nastasia [14]
3 years ago
8

Help pleaseeeeeee!!!!!!

Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

5x + 100

Step-by-step explanation:

(2x + 6) x 2 = 4x + 12

14x + 8 - 4x + 12 =

10x + 20 / 2 =

5x + 100

Hope that helps!

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Q8 Q21.) Find the amount invested at each rate.
Pavlova-9 [17]
See the attached picture:

6% = 1200
9% = 2400
12% = 3800

5 0
3 years ago
Read 2 more answers
nventing is a difficult way to make money. Only 5% of new patents earn a substantial profit. A certain city has just had30 indep
Arlecino [84]

Answer:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389

And replacing we got:

P(X \geq 2) = 1-P(X

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=30, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution to the problem

For this case we want this probability:

P(X \geq 2)

And we can use the complement rule and we got:

P(X \geq 2) = 1-P(X

And we can find the individual probabilities using the probability mass function and we got:

P(X=0) = (30C0) (0.05)^0 (1-0.05)^{30-0} =0.2146

P(X=1) = (30C1) (0.05)^1 (1-0.05)^{30-1} = 0.3389

And replacing we got:

P(X \geq 2) = 1-P(X

3 0
3 years ago
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
2 years ago
All the correct answers please
poizon [28]

B, A, D is the answer

3 0
3 years ago
M is the midpoint of C(1,7) and D(-8,-3). Find the coordinates of M.
Alex73 [517]

Answer:

hello I hope the image helps

5 0
1 year ago
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