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seraphim [82]
3 years ago
8

Classify the equilibrium solutions as asymptotically stable or unstable. Entry field with incorrect answer is unstable, is unsta

ble, is unstable. is unstable, is asymptotically stable, is unstable. is asymptotically stable, is unstable, is asymptotically stable. is asymptotically stable, is asymptotically stable, is unstable. is unstable, is asymptotically stable, is asymptotically stable.
Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Answer:

asymptotically stable.

Step-by-step explanation:

Equilibrium solutions in which solutions that starts near and then moves away from equilibrium solutions are asymptotically unstable. Equilibrium solutions which solutions starts nears and then move towards the equilibrium are asymptotically stable.

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Choose the graph. Find the angle of theta if secθ=-13/5 and tanθ is negative.
solmaris [256]

Answer:-12/5

Step-by-step explanation:

3 0
3 years ago
A. When comparing the "# of Bacteria" each hour, what is the number being multiplied by each time? *
LenaWriter [7]

Answer:

Part a) The number is 8

Part b) The initial number of bacteria is 4

Part c) y=4(8)^x

Part d) y=100(8)^x

Step-by-step explanation:

we know that

The equation of a exponential function is equal to

y=a(b)^x

where

y is the number of bacteria

x is the time in hours

b is the base of the exponential function

a is the initial number of bacteria

Part a) When comparing the "# of Bacteria" each hour, what is the number being multiplied by each time?

we know that

For x=1 h ----> y=32 bacteria

For x=2 h ----> y=256 bacteria

For x=3 h ----> y=2,048 bacteria

For x=4 h ----> y=16,384 bacteria

For x=5 h ----> y=131,072 bacteria

For x=6 h ----> y=1,048,576 bacteria

so

256/32=8

2,048/256=8

16,384\2,048=8

131,072/16,384=8

1,048,576\131,072=8

so

the base of the exponential function  b is 8

Part b) What is the initial number of bacteria? (at time zero)

we know that

The number of bacteria at time x=1 hour , divided by the number of bacteria at time x=0 must be equal to 8 (see part a)

so

\frac{32}{a}=8

solve for a

a=32/8=4\ bacteria

Part c) Write a rule for this table

we have

y=a(b)^x

we have

a=4\\b=8

substitute

y=4(8)^x

Part d) Suppose you started with 100 bacteria, but they still grew by the same growth factor. Write the function rule for this situation

In this case

a=100

b=8 ---> the growth factor is the same

so

y=100(8)^x

6 0
3 years ago
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0.00888889 I believe
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2 years ago
Do rational expressions contain logarithmic functions? A. always B. sometimes C. never
bazaltina [42]

The right answer is C. never


The quotient of two algebraic expressions is a<em> fractional expression. </em> Moreover, the quotient of two <em>polynomials</em> such as:


\frac{1}{x} \\ \\ \frac{3x-2}{1+x} \\ \\ \frac{x^2-4}{x^2+2}


is called a rational expression. So according to this definition rational expressions does not contain logarithmic functions. In fact, a rational expression is an expression that is the ratio of two polynomials like this:


f(x)=\frac{P(x)}{Q(x)} \\ \\ with \ Q(x) \neq 0

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3 years ago
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Analyzing Graphs of Functions
liberstina [14]

Answer:

The first option

Step-by-step explanation:

If you look at the graph, you'll realize that when x = 2 in the first graph, y = 4

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