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seraphim [82]
3 years ago
8

Classify the equilibrium solutions as asymptotically stable or unstable. Entry field with incorrect answer is unstable, is unsta

ble, is unstable. is unstable, is asymptotically stable, is unstable. is asymptotically stable, is unstable, is asymptotically stable. is asymptotically stable, is asymptotically stable, is unstable. is unstable, is asymptotically stable, is asymptotically stable.
Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Answer:

asymptotically stable.

Step-by-step explanation:

Equilibrium solutions in which solutions that starts near and then moves away from equilibrium solutions are asymptotically unstable. Equilibrium solutions which solutions starts nears and then move towards the equilibrium are asymptotically stable.

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15. a)
frutty [35]

Answer:

The correct answer is - A)8% B) 3%

Step-by-step explanation:

A) Let assume:

the cost price of the goods - $y.

the selling price of the goods - $x.

Given: The retailer sold at 4% discount, or 0.96x (100% - 4% = 96%). Since the goods were sold to make 20% profit, therefore it was sold for:

1.2y (100% + 20% = 120%).

Solution:

The refrigerator was sold at 13% VAT at Rs. 10848:

then,

=> 1.2y + 13%(1.2y) = 10848

=> 1.2y + 0.156y = 10848

=> 1.356y = 10848

=> y = 8000

Thus, the cp is Rs 8000.

The selling price is:

=> 0.96x = 1.2y

=> 0.96x = 1.2(8000)

=> x = 10000

The sp is Rs. 10000

For a profit of 15%, that is 1.15(8000) = 9200, the discount is:

(1 - discount)10000 = 9200

1 - discount = 0.92

Discount = 1 - 0.92 = 0.08 or 8%

B) Let C & M as cost price & marked price of the scanner machine respectively.  

(1 + 20/100)*C = 41400

or (6/5)*C = 41400

or C = (5/6)*41400

= 34500 (Rs)

(1 - 10/100)*(1 + 15/100)*M = 41400

or (9/10)*(23/20)*M = 41400

or M = (10/9)*(20/23)*41400

= 40000 (Rs)

Let R% as the reduction in the percent in discount  

(1 - 10/100 + R/100)*(1 + 15/100)*M

= (1 + 20/100 + 4/100)*C

or (9/10 + R/100)*(23/20)*40000

= (31/25)*34500

or 9/10 + R/100

= (20/23)(31/25)*(345/400)

or R/100 = 0.93 - 0.9 = 0.03

or R = 3%

7 0
3 years ago
Which is the most accurate way to estimate 51% of 57?
kow [346]
Multiply 0.57 by 51
=29.07

----------------------------------------------------------------------

8 0
3 years ago
Read 2 more answers
Find the perimeter <br><br> 18<br> 34<br> 36<br> 40
Katyanochek1 [597]
I believe that it is 34
3 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
Simplify -3y(y + 2)^2 - 5 + 6y
ser-zykov [4K]

Answer:

That'll help a lot of people in the future ^.^

Step-by-step explanation:

7 0
3 years ago
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