The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
#SPJ4
X1 = 1
x2 = 3
Hopefully this helped!
Answer:
Calculate the slope in the four intervals with the formula
m = (f(b) - f(a)) / (b - a) slope in Intervall [a; b]
m1 = (3 - 0) / (2 - 0) = 1.5
m2 = (11 - 3) / (4 - 2) = 4
m3 = (23 - 3) / (6 - 2) = 5
m4 = (23 - 11) / (6 - 4) = 6
between x = 4 and x = 6 is the correct answer.
Answer:
Alina will get $54
Step-by-step explanation:
132/11 = 12
12x4.5 = 54
Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
