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JulijaS [17]
2 years ago
11

What is the equation of the line that passes through the point (5,3) and has a slope of?

Mathematics
1 answer:
klio [65]2 years ago
7 0

Answer:

slope=2

I think that you can use demos it is a calculator just put the point and you get the answer

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4 \times 10 {}^{6}  + 7 \times  {10}^{5}  + 2 \times  {10}^{4}  + 3 \times  {10}^{3}   + 9 \times  {10}^{2}  + 1 \times  {10}^{1}  + 0 \times   {10}^{0}

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3 years ago
D+7/−3=4 Please help me
butalik [34]

Answer:

19/3

Step-by-step explanation:

I looked it up on Papamath

3 0
3 years ago
Read 2 more answers
You and six friends play a game where each person writes down his or her name on a scrap of paper, and the names are randomly di
Vanyuwa [196]
It would be 1/7 chance cause there are 7 people total but you have the 1 chance that you are going to get your own name
7 0
3 years ago
Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat
drek231 [11]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

Step-by-step explanation:

For this case we have the following probability distribution given:

X          0            1        2         3        4         5

P(X)   0.031   0.156  0.313  0.313  0.156  0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

We can verify that:

\sum_{i=1}^n P(X_i) = 1

And P(X_i) \geq 0, \forall x_i

So then we have a probability distribution

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

6 0
3 years ago
The equation y-12 describes the amount of money Anothny earns, where x is the number of hours he works and y is the amount if mo
Burka [1]

Answer=15X

$45/3 hours = $15/hour


(b) To see how much Louis makes per hour, simply plug in 1 for the hours value x:


y = 12(1 hours)


y = $12/hour


Thus Carl makes more than Louis.


(c) The equation of Carl's dollars per hour is similar to Louis':


3 0
3 years ago
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