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guajiro [1.7K]
3 years ago
13

Factor each completely. "If non-factorable, write " Non-factorable" n^3-4n^2+6n-24

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0
n^{3}-4n^{2}+6n-24
factor out n^{2} from the first two values and 6 from the last two values:
n^{2}(n-4)+6(n-4)
(n^{2}+6)(n-4) is your final answer
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See attached file. show all work.
andrew11 [14]

The point-slope form of the equation for a line can be written as

... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)

Your function gives

... f'(h) = m

... f(h) = k

a) The tangent line is then

... y = 5(x -2) +3

b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.

... y = (-1/5)(x -2) +3

_____

You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.

In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.

3 0
3 years ago
Which expression is equivalent to 4(3 plus 5) - 3 x18
Veseljchak [2.6K]

Answer:

-22

Step-by-step explanation:

6 0
3 years ago
Lol I am having an exam ....no but help
mr Goodwill [35]

Answer:

3

Step-by-step explanation:

It should be 3 because when you look at it divide them all and each one gives you 3. If it's not then sorry.

4 0
3 years ago
A line that passes through 2 or more lines are called a?<br>​
11Alexandr11 [23.1K]

Answer:

transversal

Step-by-step explanation:

1. In geometry any line which passes through or intersects  2 or more line are called a transversal.

2.Transversal are generally used in geometry of Euclidean plane to  decide whether the given set of lines  through which transversal passes are parallel or not.

8 0
3 years ago
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
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