Question

Factor each completely. "If non-factorable, write " Non-factorable" n^3-4n^2+6n-24

Answer 1

$n^{3}$-4$n^{2}$+6n-24
factor out $n^{2}$ from the first two values and 6 from the last two values:
$n^{2}$(n-4)+6(n-4)
($n^{2}$+6)(n-4) is your final answer