The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
-22
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
It should be 3 because when you look at it divide them all and each one gives you 3. If it's not then sorry.
Answer:
transversal
Step-by-step explanation:
1. In geometry any line which passes through or intersects 2 or more line are called a transversal.
2.Transversal are generally used in geometry of Euclidean plane to decide whether the given set of lines through which transversal passes are parallel or not.
Answer: The quotient is (x-2).
Step-by-step explanation:
Since we have given that
Now, we have to find the quotient of the above expression.
So, here we go:
Now, we will divide the above simplest form with g(x):
Hence, the quotient is (x-2).
