Answer:
Margin of error for 95% = 2.895
Step-by-step explanation:
We are given a sample of size 8.
First let us find mean and std deviation for this sample.
Mean = sum/8 = 108.5
Variance = E(X^2)- Mean ^2 = 12
Std dev = sqroot of 12 = 3.464
When sample is used we use standard error instead of standard deviation to find margin of error.
Std error = std dev/sq rt n = 1.225
Since sample size is very small and <30 we can use t critical value to find margin of error.
n =8 hence df = 8-1 =7
t critical for two tailed at 95% = 2.363
Margin of error = t crit * std error
=2.363(1.225) = 2.895
