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sveticcg [70]
3 years ago
6

The graph shows the distance y, in miles, of a moving train from a station over a certain period of time, x, in hours: A graph t

itled Distance Vs Time is shown with Time in hours labeled on x-axis and Distance from Station in miles labeled on y-axis. The scale on the x-axis shows the numbers 1, 2, 3, 4, 5, 6, 7, and the scale on the y-axis shows the numbers 0, 40, 80, 120, 160, 200, 240, 280, 320. The graph shows a straight line joining the ordered pairs 0, 80, and 1, 120, and 2, 160, and 3, 200, and 4, 240. What is the speed (in miles per hour) of the train and why?
 80 miles per hour, because speed is the initial value of the function 120 miles per hour, because speed is the distance traveled in unit time 240 miles per hour, because speed is the distance traveled in a certain time 40 miles per hour, because speed is the rate of change of distance

Mathematics
1 answer:
Schach [20]3 years ago
5 0
The speed of the train is equal to the slope. Why? Because speed = distance/time and because slope = rise/run. In this case, the "rise" is the change in distance while the "run" is the change in time. 

At x = 0 hours, the distance from the station is y = 80 miles. One hour later, at x = 1, the distance is now y = 120 miles. 

So,
rise = change in distance = 120-80 = 40 miles
run = change in time = 1-0 = 1 hour
slope = rise/run = 40/1 = 40

Therefore the speed of the train is 40 miles an hour

-------------------------------

Alternatively you can use the slope formula to get...

m = (y2-y1)/(x2-x1)
m = (120-80)/(1-0)
m = 40/1
m = 40

-------------------------------

Whichever method you use, the final answer is 40 mph
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4 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

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C = -10

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GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

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