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2 years ago

What is (64x^2y^3)-1/2 as radical expression?

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

3 0

Answer:

$\frac{1}{8xy \sqrt{y} }$

Step-by-step explanation:

$(64 {x}^{2} {y}^{3} )^{ - \frac{ 1 }{2} } \\ \\ = \frac{1}{(64 {x}^{2} {y}^{3} )^{\frac{ 1 }{2} } } \\ \\ = \frac{1}{ \sqrt{64 {x}^{2} {y}^{3}} } \\ \\ = \frac{1}{ \sqrt{ {(8xy)}^{2} y} } \\ \\ = \frac{1}{8xy \sqrt{y} }$

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Answer:

There are a 25% probability that Christine fails the course.

Step-by-step explanation:

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3 years ago

4(x-2)-5x>-1 grater or equal I’m bad at this

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Find the exact value of sin(cos^-1(4/5))

boyakko [2]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144

_______________

Let $\mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}$

$\mathsf{0\le \theta\le\pi,}$ because that is the range of the inverse cosine funcition.

Also,

$\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
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$\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}
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$\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
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I hope this helps. =)

Tags: <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

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