I have a 20 question geometry diagnostic due at 1 pm

Which of the following are exterior angles? Check all that apply.

s344n2d4d5 [400]

2,3,5,6 are all exterior angles because they are out of the triangle

8 0

3 years ago

Blank inches equals 20 feet

Aneli [31]

The answer is 240 simply multiply 12 x 20

7 0

3 years ago

What is the actual length of the living space if the length of the scale drawing is 16.8 centimeters? Enter your answer in the b

algol13

<h2>Answer:</h2><h2></h2><h3>21m</h3><h2></h2><h2>Explanation:</h2><h2></h2>

The diagram and complete question is shown below. We know that the length (L) of the living scale in the drawing is:

$L=16.8cm$

We also know that the scale is:

$Scale:2cm=2.5m$

Then, by using proportion we have:

$\frac{2.5m}{2cm}=\frac{x}{16.8cm} \\ \\ \\ Isolating \ x: \\ \\ x=\frac{2.5m}{2cm}(16.8cm) \\ \\ \boxed{x=21m}$

7 0

4 years ago

If the value of x-y is negative, and x and y are both positive, what can you conclude about the values of x and y?

givi [52]

If the value of x-y is negative, and x and y are both positive.

x and y are positive numbers. To get negative number while subtracting , the value of x should be less than the value of y.

For example, 5 - 9 = -4

x is 5 and y is 9 both are positive. 5 - 9 is -4 that is negative.

5 is less than 9

From this we can conclude that the value of x is less than the value of y.

6 0

3 years ago

Read 2 more answers

Which is the solution set to the given inequality |x+3|<12? x infinity(-15,9), x infinity {-15,9], x infinity (00,-15)U(9,00)

Viefleur [7K]

Answer:

Part 1) The solution set is (-15,∞) ∩ (-∞,9)=(-15,9)

Part 2) The ordered pair (1,3) is a solution of the system

Step-by-step explanation:

Part 1) we have

$\left|x+3\right|$

<u>First solution case Positive</u>

$+(x+3)$

$x$

The solution first case is the interval -------> (-∞,9)

<u>Second solution case Negative</u>

$-(x+3)$

$-x-3$

$-x$

$-x$ ------> Multiply by -1 both sides

$x>-15$

The solution second case is the interval -------> (-15,∞)

The solution set is equal to

(-15,∞) ∩ (-∞,9)=(-15,9)

Part 2) we have

$y>-2$ -------> inequality A

$x+y\leq 4$ -----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify each case

case a) (1,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

$5>-2$ ------> is true

<u>Inequality B</u>

$1+5\leq 4$

$6\leq 4$ -----> is not true

therefore

the ordered pair is not a solution

case b) (0,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

$5>-2$ ------> is true

<u>Inequality B</u>

$0+5\leq 4$

$5\leq 4$ -----> is not true

therefore

the ordered pair is not a solution

case c) (-2,-3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

$-3>-2$ ------> is not true

therefore

the ordered pair is not a solution

case d) (1,3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

$3>-2$ ------> is true

<u>Inequality B</u>

$1+3\leq 4$

$4\leq 4$ -----> is true

therefore

the ordered pair is a solution

6 0

3 years ago