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kkurt [141]
3 years ago
6

Jovie is maintaining a camp fire. She has kept the fire steadily burning for 101010 hours with 151515 logs. She wants to know ho

w many hours (h)(h)left parenthesis, h, right parenthesis she could have kept the fire going with 999 logs. She assumes all logs are the same.
How many hours can Jovie keep the fire going with 999 logs?
Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:666 hours

Step-by-step explanation: The reason is that if you turn the problem into an equation it would be h=Lx. h= hours. L=how long the log lasts and x=how many logs. So when you plug in the numbers you get 101010=L*151515. So we need to find L. What you do is you divide both sides by 151515 since it is the opposite of multiplication. 151515/151515 gets crossed out and 101010/151515 is .6666666666666 irrational. So the equation now looks like .666666 irrational=L. So .66666 irrational is your L. Know you plug .666666 irrational into your original equation. Which is now h=.6666 irrational*x. So to find how long the fire keeps on burning with 999 logs you just plug 999 into x and now your equation looks like this h=.6666 irrational*999. If you multiply .6666 irrational by 999 your final answer is 666.

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Answer:

<em>A(2,3) has a distance of 2 to the y-axis</em>

<em>B(-3,2) has a distance of 3 to the y-axis</em>

<em>C(2,-3) has a distance of 2 to the y-axis</em>

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Step-by-step explanation:

<u>Distance of a point to an axis</u>

Given a point (x,y) its rectangular coordinates are defined as the distances from the point to each axis with respect to the origin (0,0).

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Generally speaking, point (x,y) has a distance |x| from the y-axis and a distance |y| from the x-axis.

The absolute value bars are used because the distance is always positive.

Apply that to the points:

A(2,3) has a distance of 2 to the y-axis

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3 years ago
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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

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V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

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r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

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Hence, the results are accurate and consistent!

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