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kherson [118]
3 years ago
6

Which figure could be rotated the least amount of degrees to be carried onto itself

Mathematics
2 answers:
jeka943 years ago
8 0
Regular octagon.
Regular shapes take the least amount of degrees to rotate on themselves. However, out of all of them, the octagon has the most sides and thus also the least amount of degrees in rotating.

Hope this helps :)
kherson [118]3 years ago
7 0
A circle could.
Among the regular polygons, it's the one with the most sides.
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To rent a moving truck for the day, it costs $50 plus $3 for every mile driven. Write an algebraic expression for the cost to re
malfutka [58]

Multiply the cost per mile by number of miles “m” and add that amount to the $50:

Total = 3m + 50

3 0
2 years ago
Read 2 more answers
5x^{4}-7x^{3}-5x^{2}+5x+1-0
den301095 [7]

Answer:

5x^4 -7x^3-5x^2+5x+1

Step-by-step explanation:

Hey!

You would just add all the numbers up, and by making sure that you combine all like terms. In this case it is just 1-0 = 1 and so the solution would be the same as your question but with a 1 and you would get rid of the -0.

Hope this helps!

7 0
3 years ago
URGENTTT<br><br><br> 3+3 x 7^2 - 9 x 10
charle [14.2K]

Answer: 60

Step-by-step explanation:

8 0
3 years ago
Please help! i was wondering how you would solve this question!
Anon25 [30]

Answer:  C.  150 km²

<u>Step-by-step explanation:</u>

Use similar triangle proportion to find x:

\dfrac{x}{4.5}=\dfrac{15.3+7.4}{7.4}\\\\\\x=\dfrac{4.5(22.7)}{7.4}\\\\\\x=13.8\\\\\text{Notice that x is the diameter of the circle}\implies r=\dfrac{13.8}{2}=6.9\\\\\\\text{Find the area of the circle using }A=\pi r^2\\A=\pi (6.9)^2\\\\.\ =\pi (47.6)\\\\.\ =149.6\\\\.\ \approx150

4 0
3 years ago
What is the sum of the exterior angles, one at each vertex, of a polygon with 20 sides?A.20B.360C.180D. We need more information
ale4655 [162]

The measure of an exterior angle in a polygon with n sides is given by:

a_n=\frac{360}{n}

So, for n = 20, we have the measure of the exterior angles of the polygon with 20 sides:

\begin{gathered} a_{20}=\frac{360}{20} \\ a_{20}=18\degree \end{gathered}

Now, to find the sum of all exterior angles, let's multiply the exterior angles by the number of sides of the polygon:

\begin{gathered} S_{20}=a_{20}\cdot n \\ S_{20}=18\cdot20 \\ S_{20}=360\degree \end{gathered}

Therefore the sum is equal to 360°, correct option: B.

(The sum of exterior angles of a polygon with n sides is always equal to 360°)

7 0
1 year ago
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