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lara [203]
4 years ago
8

Solve the inequality (24x+4)^-1<0

Mathematics
2 answers:
Basile [38]4 years ago
6 0
X<-1/6

(24x+4)^-1<0
1/(24x+4)<0
1/(4(6x+1))<0 - denominator needs to be less than 0
4(6x+1)<0
6x+1<0
6x<-1
x<-1/6
sleet_krkn [62]4 years ago
3 0
I think you meant  <span>(24x+4)^(-1)<0.

This is equivalent to  1 / [4(6x+1)] < 0.

We must determine the set of values of x for which 6x+1 is not equal to zero and 6x+1 is less than 0 (because  </span>1 / [4(6x+1)] < 0  for such values).

Solve 6x+1 < 0.    6x+1<0 becomes    6x < -1,    or   x < -1/6

This divides the number line into two halves:  (- infinity, -1/6) and (-1/6, infinity).

From each half, choose an x value not equal to -1/6.  If the original inequality is then true, you have found the interval that solves it.  If false, choose the other interval to represent your solution.  
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which of the following is not a way to represent the solution of the inequality 8x − (5x 4) greater than or equal to −31? a. x g
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Can someone help me pls
alisha [4.7K]

sorry i can't solve

i'm sorry

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