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Alenkinab [10]
3 years ago
9

Identify the point on the line 3x - 2y = 4 that has a y value of 7. Write your

Mathematics
1 answer:
Alik [6]3 years ago
5 0

Answer:

3x-2(7)=4

3x-14=4

3x=4+14

<u>3x</u>=<u>18</u>

3. 3

x= 6

You might be interested in
Is anyone good at algebra and solving one variable inequalities? I need help!!
IRINA_888 [86]

Answer:

Let Quarters be q and Dimes be d

q + d >20

2q +d >20

d > 20 - 2q

Hope This Helps! (and that you get it right!)

7 0
3 years ago
Write 56/90 as a decimal.
gizmo_the_mogwai [7]
56/90

" / " means divide

56 divided by 90 = 0.62 with a line over the 2 because it is repeating
5 0
3 years ago
Read 2 more answers
Need help plsssss and thanks
NeTakaya
Why is that gal there
6 0
3 years ago
6. The base of a triangular field is three times its height. If the cost of cultivating the field
dedylja [7]

Answer:

base = 519.62, height = 173.21 m

Step-by-step explanation:

Let the base and height of the triangle be represented by b and h respectively.

Thus,

b = 3h

Area of a triangle = \frac{1}{2} x base x height

For the given triangle,

area = \frac{1}{2} x b x 3h

       = \frac{3}{2}bh

Area of the triangle = \frac{3}{2}bh

To determine the number of hectares,

36 per hectare = 486

hectare = \frac{486}{36}

             = 13.5

numbers of hectares = 13.5

Area of the hectares = number of hectares x 10 000 m²

                                   = 13.5 x 10 000

                                  = 135000

Total area of the hectares = 135 000 m²

So that,

area of the hectares = area of the triangle

area of the triangle = \frac{3}{2}bh

135 000 = \frac{3}{2}bh

270000 = 3bh

bh = \frac{270000}{3}

     = 90000

bh = 90000

But, b = 3h

3h x h = 90000

3h^{2} = 90000

h^{2}  = \frac{90000}{3}

     = 30000

h = \sqrt{30000}

  = 173.2051

h = 173.21 m

So that,

b = 3 x 173.2051

  = 519.6153

b = 519.62

Therefore, the base of the triangle is 519.62 m, while the height is 173.21 m.

7 0
4 years ago
Given the sequence 12, 6, 3, 3/2, ..., identify the tenth term. Show your work.
Sunny_sXe [5.5K]
U have a geometric sequence. To find the common ratio, divide the second term by the first term. 6/12 = 1/2

an = a1 * r^(n-1)
n = term to find = 10
a1 = first term = 12
r = common ratio = 1/2 
now we sub

a(10) = 12 * 1/2(10 - 1)
a(10) = 12 * 1/2^9
a(10) = 12 * 1/512
a(10) = 12/512 reduces to 3/128 ,<== ur 10th term
7 0
4 years ago
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