Question

The ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and

Answer 1

Answer:

The age difference between oldest the youngest is of 48 years.

Step-by-step explanation:

We can solve this question using a system of equations.

I am going to say that:

Kissi's age is x.

Esinam's age is y.

Lariba's age is z.

The ratio of the ages of Kissi and Esinam is 3:5

This means that $\frac{x}{y} = \frac{3}{5}$, so $5x = 3y$

That of Esinam and Lariba is 3:5

This means that $\frac{y}{z} = \frac{3}{5}$, so$5y = 3z$

The sum of the ages of all 3 is 147 years

This means that $x + y + z = 147$

What is the age difference between oldest the youngest

z is the oldest

x is the youngest.

First i will find y.

We have that, from the equations above: $x = \frac{3y}{5}$ and $z = \frac{5y}{3}$

So

$x + y + z = 147$

$\frac{3y}{5} + y + \frac{5y}{3} = 147$

The lesser common multiple between 5 and 3 is 15. So

$\frac{3*3y + 15*y + 5*5y}{15} = 147$

$49y = 147*15$

$y = \frac{147*15}{49}$

$y = 45$

Youngest:

$x = \frac{3y}{5} = \frac{3*45}{5} = 27$

Oldest:

$z = \frac{5y}{3} = \frac{5*45}{3} = 75$

Difference:

75 - 27 = 48

The age difference between oldest the youngest is of 48 years.