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3 years ago

Help me solve this problem please

Mathematics

2 answers:

Ulleksa [173]3 years ago

4 0

Center-radius equation of a circle with a center at (5,3) and radius 5 is:
(x−5)^2+(y−3)^2=25

Standard equation of a circle with a center at (5,3) and radius 5 is:
x^2-10x+y^2−6y+9=0

ad-work [718]3 years ago

3 0

I think you count the squares in the middle or radius ?

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The sum of two numbers is 15 and

tensa zangetsu [6.8K]

Answer:

Smaller Number=4, Larger Number=11

Step-by-step explanation:

I just guessed and checked

6 0

3 years ago

A person's metabolic rate is the rate at which the body consumes energy. Metabolic rate is important in studies of weight gain,

cupoosta [38]

Let m be mean

Mean= sum/ n

Mean= (1720+1687+1367+1614+1460+1867+1436) / 7

m= 11151 / 7

M= 1593

Mean= 1593

Standard deviation

|x-m|^2

For 1st: |1720-1593|^2=8836

For 2nd: |1687-1593|^2=10201

For 3rd: |1367-1593|^2=51076

For 4th: |1614-1593|^2=441

For 5th: |1460-1593|^2=1689

For 6th: |1867-1593|^2=75076

For 7th: |1436-1593|^2=24649

Summation of |x-m|^2 = 171968

Standard deviation sample formula is:

S.D = sqrt((summation of |x-m|^2) / n-1)

S.D=sqrt(171968/6)

S.D=sqrt(28661.33)

S.D=169.30

Standard deviation is 169.30

3 0

3 years ago

Julie was looking at the architect's blueprint of her house. The scale on the blueprint was inch = 1 foot. On the blueprint, wha

coldgirl [10]

12 inches by 16 inches

7 0

3 years ago

What are the key features of a graph of a quadratic equation with only complex solutions

dybincka [34]

Answer:

If D< 0, the roots of the quadratic equation will b complex.

Step-by-step explanation:

Let $ax^{2} + bx + c =0$ is the given quadratic equation.

So, if the Discriminant (D) = $b^{2} - 4ac < 0$ , the the equation will have only complex solutions.

Complex roots are represented in the form of $(x \pm iy)$

1. x represents the X axis (real) co ordinate,

y represents the Y axis (imaginary) coordinate

2. Also, the graph of the with equation D < 0 NEVER CROSSES the X - axis, as there are no real roots of the equation, only complex roots.

3. Here. roots are always identical but are opposite in signs. Such pair or roots with opposite sign are called CONJUGATE PAIRS.

4 0

3 years ago

Grandma has just finished baking a large rectangular pan of brownies. She is planning to make rectangular pieces of equal size a

Nikitich [7]

Answer: 60

Step-by-step explanation:

Let the side lengths of the rectangular pan be m and n. It follows that (m-2) (n-2)= $mn/2$

So, since haf of the brownie pieces are in the interior. This gives 2 (m-2) (n-2) =mn

mn- 2m - 2n- 4 = 0

Then Adding 8 to both sides and applying, we obtain (m-2) (n-2) =8

Since now, m and n are both positive, we obtain (m,n) = (5,12), (6,8) (up to ordering). By inspection, 5. 12 = 60

which maximizes the number of brownies in total which is the greatest number.

Hope that helped! =)

7 0

3 years ago