Question

The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle? Let w represent the width of the rectangle.

Answer 1

First off,we need to understandthe perimeter of a rectangle:
$2(width + height)$

We can then proceed to find the width. As it is 6 ft more than it's length,it can be written in:

$w + 6$
We can then find the equation of the perimeter:

$2((2 + w) + w) = 68 \\ 2(2 + 2w) = 68 \\ 4 + 4w = 68 \\ 4(1 + w) = 68 \\ 1 + w = \frac{68}{4} \\ w = 17 - 1 \\ w = 16$

When the width is 16ft, the length is:
$16 - 6 \\ = 10$
The length is 10 ft.

Therefore the dimention of the rectangle is 16ft by 10ft.

Hope it helps!