Answer:
Bridget will get the amount as £26.
Step-by-step explanation:
Given:
Amount Stephen gets = £65
Amount shared in ratio = 5:2
We need to find the amount Bridget gets.
Solution:
Let the common factor in the ratio be
.
Amount Stephen gets = ![5x](https://tex.z-dn.net/?f=5x)
Amount Bridget gets = ![2x](https://tex.z-dn.net/?f=2x)
But we know that;
Amount Stephen gets = £65
so we can say that;
![5x=65](https://tex.z-dn.net/?f=5x%3D65)
Now dividing both side by 5 we get;
![\frac{5x}{5}=\frac{65}{5}\\\\x=13](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B5%7D%3D%5Cfrac%7B65%7D%7B5%7D%5C%5C%5C%5Cx%3D13)
So now we get;
Amount Bridget gets = ![2x=2\times 13 = \£26](https://tex.z-dn.net/?f=2x%3D2%5Ctimes%2013%20%3D%20%5C%C2%A326)
Hence Bridget will get the amount as £26.
Assuming no student was born on Leap Day, and that birthdays are as likely to occur on one day as any other, each student has
![\dfrac1{365}](https://tex.z-dn.net/?f=%5Cdfrac1%7B365%7D)
probability of being born on a particular day. So if one student's birthday was, say, 1 January, the probability that another student was born on 2 January is
![\dfrac{364}{365}](https://tex.z-dn.net/?f=%5Cdfrac%7B364%7D%7B365%7D)
.
The probability, then, of having the next student born on 3 Januaray is
![\dfrac{363}{365}](https://tex.z-dn.net/?f=%5Cdfrac%7B363%7D%7B365%7D)
.
Continuing in this fashion, for 25 students you would find that no two share a birthday with probability
He made about $300 more this week.
Answer:
u will get 1.44 per meter, if thats what ur looking for
Step-by-step explanation: