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IrinaVladis [17]
4 years ago
7

Meg is starting a day-care center for the people in her community. She decided to charge $25 per day per child, out of which $5

is her expenditure per child per day. If Meg's target is to earn $2,000 over 20 weekdays in June, the minimum number of kids she has to watch per weekday that month is
Mathematics
2 answers:
attashe74 [19]4 years ago
6 0
If I figured correctly it is 5 kids. Sorry if wrong!
Alex4 years ago
4 0

Answer:

5

Step-by-step explanation:

Let the number of kids be x

We are given that she charge $25 per day per child

So, she charge for x kids per day = $25x

So,charge for x kids for 20 days = 20 \times 25 x = 500x

Her expenditure per day per kid is of $5

So, her expenditure per day for x kids = $5x

So, her expenditure 20 days for x kids =  20 \times5 x = 100x

So, she gained for taing care of x kids for 20 days = 500x-100x = 400x

Since we are given that her target is to earn $2000

So, A.T.Q

400x= 2000

x= \frac{2000}{400}

x=5

Hence the minimum number of kids she has to watch per weekday that month is 5

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Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

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3 years ago
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7 0
3 years ago
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FromTheMoon [43]
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3 years ago
What is the sum of 3 consecutive odd integers is -39
trapecia [35]
Answer: The three consecutive odd integers are:  -15, -13, and -11 .
_______________________________________________________
Explanation:
_____________________________________________
  x + (x + 2) + (x + 4) = -39 ;
_____________________________________________
 in which "x" is one of the integers, 
           "(x + 2)" is the next consecutive odd integer;
           "(x + 4)"  is the third consecutive odd integer.
__________________________________________
By solving for "x", we can solve for each of three (3) consecutive odd integers.
________________________________________________________
     x + (x + 2) + (x + 4) = -39  ;
_________________________________________________________
          1x + 1x + 2 + 1x+ 4 = -39 ;
_____________________________________________________  
                   3x + 6 = -39 ;
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               Subtract  "6" from EACH side of the equation:
______________________________________________
                    3x + 6 − 6  =  -39 <span>− 6 ;
____________________________________________________
        to get:   3x = -45 ;
____________________________________________________
           Divide EACH side of the equation by "3" ;
____________________________________________________
                 3x / 3 = -45 / 3 ;
_____________________________________________________
        to get:   x = -15 ;
______________________________________________________
     x + 2 =  -15 + 2 = -13 ;
_______________________________________________________
     x + 4 =  -15 + 4 =  -11 .
___________________________________________________
Are: -15, -13, and -11 ;  Consecutive odd integers?  YES!
___________________________________________________
Does:  -15 + (-13) + (-11)  =? = -39 ??
_____________________________________________________
           -15 </span>− 13 <span>− 11 = ? 39 ??  YES!
____________________________________________________
Answer: The three consecutive odd integers are:  -15, -13, and -11.
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4 0
3 years ago
If f(x)=4x^2+1 g(x)=x^2-5find (f-g)(x)
JulsSmile [24]
ANSWER: 3x^2 + 6

4x^2 + 1 - (x^2 - 5) = 3x^2 + 6
7 0
3 years ago
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