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saw5 [17]
3 years ago
9

2,45,250 students appeared for an entrance examination. If 94,750 students did not get admission, find how many students got adm

ission.
can i please get the answer
Mathematics
2 answers:
Lorico [155]3 years ago
6 0

Answer:

2.45.250- 94.750

= 92. 2975. this is the learners who got the admission

tatuchka [14]3 years ago
5 0

Answer:

1,50,500 students

Step-by-step explanation:

Hope this helps... vote as brainliest

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If Janis and Melanie make bracelets one afternoon during Choice time. They make six bracelets each. They feel generous and give
dusya [7]
3 each left. Hope it helped
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3 years ago
How can division patterns help us divide multiples of 10
KengaRu [80]
Division using multiples of 10 is different than how most of us learned how to divide. <span>The idea of multiple is what number can 10 go into without a remainder. That is easy. Ten ends in a zero. Thus 10 goes into numbers ending in zero. An example is 60. Ten ends in a zero; 60 ends in a zero. It will divide evenly. </span>
7 0
3 years ago
a solid consists of cylinder surmounted by a right circular cone. The height of the cone is 2h. If the volume of the solid is 3
Mademuasel [1]

Answer:

height of cylinder = 4/3 h

Step-by-step explanation:

The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.

volume of the solid = volume of cylinder + volume of cone

volume of the solid = πr²h + 1/3πr²h

let

height of the cylinder = H

recall

the height of the cone = 2h

volume of the solid = πr²h + 1/3πr²h

3(1/3πr²2h) = πr²H + 1/3πr²2h

2πr²h = πr²H + 2/3 πr²h

πr²(2h) = πr²(H + 2/3 h)

divide both sides by πr²

2h = H + 2/3 h

2h - 2/3h = H

H = 6h - 2h/3

H = 4/3 h

height of cylinder = 4/3 h

8 0
3 years ago
There are 6 squares and 2 circles. What is the simplest ratio of circles to total shapes?
Sunny_sXe [5.5K]

Add to find the total number of shapes.

6 + 2 = 8

Circles to total amount of shapes -> 2:8

Divide 2 to both sides.

2/2:8/2

1:4

Therefore, the answer is 1:4

Best of Luck!

4 0
3 years ago
Read 2 more answers
Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
fgiga [73]

Answer:

  • QN = 3√7
  • OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

  DQ = (3 units)·3 = 9 units

  KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

  KI² = KO² +OI²

  4² = 3² +OI²

  OI = √(16 -9)

  OI = √7

  QN = 3·OI = 3√7

8 0
3 years ago
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