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3 years ago

7

Mr. Plum's math class of 25 students had an average of 85 on a test. Miss Scarlett's class of 22 students had an average of 87 o

n the same test. What is the average of the two classes combined?

2 answers:

Monica [59]3 years ago

6 0

Use ((85x25)+(22x87))/ 47 for this to get the answer of about 86 (rounded)

maria [59]3 years ago

3 0

Add the two averages together and then divide it by 2. Thats your answer.

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Peter tracks the goals he scores in 9 soccer games. In two games Peter scored 2 goals each, in one game he scored 0 goals, in tw

Reika [66]

The average number of goals per game Peter scores, rounded to one decimal place is 1.6

<u><em>Explanation</em></u>

In first two games Peter scored 2 goals each. So, total score in two games = (2×2)= 4

In one game he scored 0 goal and in next two games he scored 3 goals each, so the total is (3×2)= 6

In the last four games he scored 1 goal in each, so the total is (1×4)= 4

So, the total score in all $9$ games $=4+0+6+4=14$

Thus, the average number of goals $= \frac{14}{9}= 1.5555....$

So, the average number of goals per game Peter scores, rounded to one decimal place is 1.6

3 0

3 years ago

Read 2 more answers

Triangle ABC is dilated by a scale factor of 2 with a center of dilation at the origin. Finish the rule for this dilation.

Vitek1552 [10]

Abc is your answer

Step-by-step explanation:

you said ABC

4 0

3 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago

5. A square pyramid has a slant height of 5 meters. The perimeter of the base is 32 meters. Find the surface area of the pyramid

Agata [3.3K]

Step-by-step explanation:

Answer to A square-based pyramid has a slant height of 10 meters and a side base of 16 meters. What is the surface area? by Janet Heberling https://www.quora.com/A-square-based-pyramid-has-a-slant-height-of-10-meters-and-a-side-base-of-16-meters-What-is-the-surface-area/answer/Janet-Heberling-1?ch=15&oid=253187394&share=f14a7431&srid=hdLI1f&target_type=answer

4 0

3 years ago

Read 2 more answers

2x+3y=12 find y and x intercepts

lord [1]

Answer:

Linear function 2x+3y=12 .

Step-by-step explanation:

To find y-intercept , make x=0 :

3y = 12

y = 12/3

y = 4 .

To find x-intercept , make y=0 :

2x = 12

x = 12/2

x = 6 .

<u> ! Hope this will help you !</u>

8 0

4 years ago