All categories

2 years ago

Plsss hurry!!!! i rlly need help

Mathematics

2 answers:

Lostsunrise [7]2 years ago

3 0

Answer:

41 21/25

Step-by-step explanation:

38 1/25 + 3 4/5 = 41 21/25

marta [7]2 years ago

3 0

I think it’s 41 21/25

You might be interested in

In a parallelogram consecutive angles are

Elenna [48]

Answer:

because they are supplementary angles

4 0

3 years ago

What is the rate of 78 and 2

NeTakaya

78/2
= 39 is the answer

8 0

3 years ago

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

3 years ago

( PLEASE HELP )Use the table to write a proportion .

Margaret [11]

8/6 and then m/16 is the correct answer

7 0

3 years ago

Please help! ill give brainliest!

prohojiy [21]

B

Step by step equation

7 0

3 years ago