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GaryK [48]
3 years ago
5

The sum of three certain consecutive numbers is 240. Find the three numbers. [Hint: Let x stand for the smallest number. Since t

he numbers are consecutive, add 1 to get the second number (x + 1) and add 2 to get the third number (x + 2).]
Mathematics
1 answer:
aleksley [76]3 years ago
7 0
Write an equation based on the problem in the terms of x and solve the equation
first number + second number + third number = 240
x + x + 1 + x + 2 = 240
3x + 3 = 240
3x = 240 - 3
3x = 237
  x = 237/3
  x = 79
The smallest number, x, is equal to 79

Find the next two numbers
the second number = x + 1
the second number = 79 + 1
the second number = 80

the third number = x + 2
the third number = 79 + 2
the third number = 81

ANSWER: The three numbers are 79, 80, 81
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Step-by-step explanation:

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cos(55+35) = cos(55)cos(35) - cos(90-55)cos(90-35)

cos(55+35) = cos(55)cos(35) - cos(35)cos(55)

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4 0
3 years ago
The graphs of f(x) and g(x) are shown below:
rosijanka [135]
<h2>Answer:</h2>

Option: C is the correct answer.

            C.)   x = −3.8, 3

<h2>Step-by-step explanation:</h2>

The function f(x) is given by:

           f(x)=x^2-x-12

and the function g(x) is given by:

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Now, we are asked to find the solution of the equation:

        f(x)=g(x)

i.e. we have to find the value of x such that both the functions are equal i.e.

x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0

Now, on solving the equation using the quadratic formula i.e. the solution of the equation:

ax^2+bx+c=0

is given by:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=5,\ b=4\ and\ c=-57

Hence, the solution is given by:

x=\dfrac{-4\pm \sqrt{4^2-4\times 5\times (-57)}}{2\times 5}\\\\i.e.\\\\x=\dfrac{-4\pm \sqrt{16+1140}}{10}\\\\i.e.\\\\x=-3.8\ and\ x=3

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3 years ago
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Answer:

y ≤ -5

Step-by-step explanation:

6 0
2 years ago
What is 6y−12=−3x in standard form?
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3 years ago
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