The answer you put is correct
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
3) an $8 delivery fee and $1.50 per litre of water
This is because the $8 is a constant baseline, then adding $1.50 times the amount of litres purchased.
Answer:
311/9
Step-by-step explanation:
trust me im big brain lol hope this helps
Answer:
This is a false statement:
Step-by-step explanation:
According to Remainder Theorem dividing the polynomial by some linear factor x + a, where a is just some number. As a result of the long polynomial division, you end up with some polynomial answer q(x) (the "q" standing for "the quotient polynomial") and some polynomial remainder r(x).
P(x)= (x+/-a) q(x)+r(x)
P(x)=(x+a) q(x)+r(x). Note that for x=-a
P(-a)=(-a+a) q(-a)+r(-a)= 0* q(-a)+ r(-a)
P(-a)=r(-a)
It means that P(-a) is the remainder not P(a)
Thus the given statement is false....
