Can u guys help me plz

Mathematics

1 answer:

Lunna [17]4 years ago

8 0

Set it up as a propotion and cross multiply. 10/23=15/x answer is 34.5

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There are 5 times as many males as females on the maths course at university. What fraction of the course are female? Give your

koban [17]

Answer: 1/6

Step-by-step explanation: Let the no of females be x

The no of males be 5x

The total no of males and females in the math course be 5x+x= 6x

The fraction of females is x/6x = 1/6

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3 years ago

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Fudgin [204]

Ok so i only did 9-18
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3 years ago

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For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.