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nata0808 [166]
4 years ago
8

Can u guys help me plz

Mathematics
1 answer:
Lunna [17]4 years ago
8 0
Set it up as a propotion and cross multiply. 10/23=15/x answer is 34.5
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The equation |2x-8|+3= 5 has 2 solutions. These
Serggg [28]

Answer:  x=8  x=0

Step-by-step explanation:

4 0
3 years ago
When Mei does 17 push-ups and 6 sit-ups, it takes a total of 35 seconds. In comparison, she needs 41 seconds to do 20 push-ups a
Romashka [77]

Answer:

It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

Step-by-step explanation:

Given:

Let the time taken for push-ups be 'x'.

Let the time taken for sit-ups be 'y'.

Now Given:

17 push-ups and 6 sit-ups, it takes a total of 35 seconds.

So we can say that;

17x+6y=35 \ \ \ \ equation \ 1

Also Given:

41 seconds to do 20 push-ups and 7 sit-ups.

so we can say that;

20x+7y=41 \ \ \ \ equation \ 2

Now Multiplying equation 1 by 7 we get;

7(17x+6y)=35\times7\\\\119x+42y= 245 \ \ \ \ equation \ 3

Now Multiplying equation 2 by 6 we get;

6(20x+7y)=41\times6\\\\120x+42y = 246 \ \ \ \ equation\ 4

Now Subtracting equation 3 from equation 4 we get;

120x+42y-(119x+42y)=246-245\\\\120x+42y-119x-42y=1\\\\x=1\ sec

Now substituting the value of x in equation 1 we get;

17x+6y=35\\\\17\times1+6y=35\\\\17+6y=35\\\\6y=35-17\\\\6y= 18\\\\y=\frac{18}6 = 3\ seconds

Hence It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

7 0
3 years ago
What is the mechanical advantage of a hockey stick that is gripped at point D and hits the puck at point B?
RideAnS [48]

Answer:

Mechanical advantage = Effort distance/Resistance distance

Effort distance = D - Fulcrum = 0.5 m

Resistance distance = A - Fulcrum = 2.0 m

Then,

Mechanical advantage = 0.5/2 = 0.25 

Hockey stick is an example of third class where mechanical advantage is less than one as the speed of the end of point A is critical.

5 0
2 years ago
Read 2 more answers
Find f(-5) and f(12) for each piecewise function f(x){-4x+3 if x<3
Law Incorporation [45]
<h3>Answers:</h3>
  • f(-5) = 23
  • f(12) = 433

==================================================

Explanation:

The given piecewise function is

f(x) = \begin{cases}-4x+3 \ \text{ if } \ x < 3\\-x^3 \ \text{ if } \ 3 \le x \le 8\\3x^2+1 \ \text{ if } \ x > 8\end{cases}

At first piecewise functions may be strange confusing things, but they aren't so bad. I like to think of it like this: f(x) is a function that changes its identity based on what the input x is. We have three situations

  • f(x) = -4x+3 when x < 3
  • f(x) = -x^3 when 3 \le x \le 8
  • f(x) = 3x^2+1 when x > 8

In a sense, we have three different functions but they are combined somehow.

If x is smaller than 3, then we go for the first definition. Or if x is between 3 and 8, then we go for the second definition. Or if x is larger than 8, then we go for the third definition.

-----------------------

f(-5) means f(x) when x = -5. We see that -5 is smaller than 3, so x = -5 makes x < 3 true. We'll use the first definition

f(x) = -4x+3

f(-5) = -4(-5)+3

f(-5) = 20+3

f(-5) = 23

------------------------

Now the input is x = 12. This is larger than 8. In other words, x = 12 makes x > 8 true. We'll use the third definition

f(x) = 3x^2+1

f(12) = 3(12)^2+1

f(12) = 3(144)+1

f(12) = 432+1

f(12) = 433

------------------------

Side notes:

  • We won't use the second definition since we don't have any x inputs between 3 and 8
  • To say "less than or equal to" on a keyboard, you can write "<=" without quotes. For example, x \le 5 is the same as x<=5
3 0
4 years ago
What is the solution to the system of equations represented by the two equations?
nexus9112 [7]
Just substitute the first equation into the second and solve for x: <span><span>32</span>x=−<span>12</span>x+4⟹2x=4⟹x=2</span><span>Now, since y = 3/2 * x, we have y = 3 and we are done.</span>
8 0
3 years ago
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