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Simora [160]
3 years ago
8

(2a+b)^2÷(3b-1) when a= -2 and b=5

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

 | 1 | 5
- | | 1
 | 1 | 4:
(5 - 2×2)^2/14

2 (-2) = -4:
(-4 + 5)^2/14

5 - 4 = 1:
1^2/14

1^2 = 1:

Answer: 1/14
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Factor the difference of the perfect square. If the binomial will not factor, write prime.
KATRIN_1 [288]
Easy peasy, this is a representation of differnce of 2 perfect squares
a^2-b^2=(a-b)(a+b)
3 0
3 years ago
Read 2 more answers
HELP THIS is due in 30 mins Renaldo described the translation of the graph of f(x) = x2 related to g(x) = (x + 2)2 - 6 as 2 unit
stiv31 [10]

Answer:

See below

Step-by-step explanation:

Recall that we need to use the equation y=a(x-h)^2+k. This means that h=-2 instead of 2 otherwise it would've been (x-2)^2-6. So Renaldo made the mistake of identifying h as 2 instead of -2. The second mistake Renaldo made is that since k=-6, there should be a vertical shift of 6 units down not 2.

5 0
3 years ago
Use the theoretical method to determine the probability of the following event. A randomly selected person has a birthday in Nov
MakcuM [25]

Answer:

There is an 8.22% probability that a randomly selected person has a birthday in November.

Step-by-step explanation:

The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.

A randomly selected person has a birthday in November

There are 365 days in a year, so the number of total outcomes is 365.

There are 30 days in november, so the number of desired outcomes is 30.

So the probability is

P = \frac{30}{365} = 0.0822

There is an 8.22% probability that a randomly selected person has a birthday in November.

3 0
3 years ago
Find all the zeros of the function <br> g(x)=x^3-4x^2-x+22
vagabundo [1.1K]

Answer:

x = -2, x = 3 − i√8, and x = 3 + i√8

Step-by-step explanation:

g(x) = x³ − 4x² − x + 22

This is a cubic equation, so it must have either 1 or 3 real roots.

Using rational root theorem, we can check if any of those real roots are rational.  Possible rational roots are ±1, ±2, ±11, and ±22.

g(-1) = 18

g(1) = 18

g(-2) = 0

g(2) = 12

g(-11) = 1782

g(11) = 858

g(-22) = -12540

g(22) = 8712

We know -2 is a root.  The other two roots are irrational.  To find them, we must find the other factor of g(x).  We can do this using long division, or we can factor using grouping.

g(x) = x³ − 4x² − 12x + 11x + 22

g(x) = x (x² − 4x − 12) + 11 (x + 2)

g(x) = x (x − 6) (x + 2) + 11 (x + 2)

g(x) = (x (x − 6) + 11) (x + 2)

g(x) = (x² − 6x + 11) (x + 2)

x² − 6x + 11 = 0

Quadratic formula:

x = [ 6 ± √(36 − 4(1)(11)) ] / 2

x = (6 ± 2i√8) / 2

x = 3 ± i√8

The three roots are x = -2, x = 3 − i√8, and x = 3 + i√8.

5 0
3 years ago
Evaluate the numerical expression. 9.6 – 10.8 ÷ 0.6
madreJ [45]

Hi there!

Answer:

<u><em>C.-8.4</em></u>

Step-by-step explanation:

divide by the numbers.

10.8-0.6=18.0=18

9.6-18

subtract the numbers.

9.6-18=-8.4

=-8.4

Hope this helps!

-Charlie

Have a great day!

4 0
3 years ago
Read 2 more answers
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