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Simora [160]
3 years ago
8

(2a+b)^2÷(3b-1) when a= -2 and b=5

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)

3×5 = 15:
(5 - 2×2)^2/(15 - 1)

 | 1 | 5
- | | 1
 | 1 | 4:
(5 - 2×2)^2/14

2 (-2) = -4:
(-4 + 5)^2/14

5 - 4 = 1:
1^2/14

1^2 = 1:

Answer: 1/14
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Alex wrote 103.903 in expanded form as 100+3 x 1+9 x 1/100 +3 x 1/1000. Explain his mistake then tell how to correct it.
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Your mistake was in this part  9 x 1/100 . After the decimal point the place value starts with tenths so you should write 9 x 1/10 .

Place values

Before the decimal point

3 ones = 3 x 1

0 tens = 0 x 10

1 hundreds = 1 x 100

After the decimal point

9 tenths = 9 x 1/10

0 hundredths = 0 x 1/100

3 thousandths= 3 x 1/1000

1 x 100 + 0 x 10 + 3 x 1 + 9 x 1/10 + 0 x 1/100 + 3 x 1/1000

  100     +    0     +   3    +    0.9      +     0        +    0.003

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8 0
3 years ago
Read 2 more answers
What is the slope of the line shown below?
galina1969 [7]

Answer:

B

Step-by-step explanation:

answer is slope =2

use formula y2-y1 over x2-x1

two points of graph is (6,6) and (1,-4)

since 6 and -4 are both y, we take 6-(-4) over 6-1

we get 2

ask for further explanation if you need!!❤

5 0
3 years ago
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