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timofeeve [1]
1 year ago
12

Research suggests that students could benefit from later school starting times. A school administrative team is considering a pr

oposal to move the starting time of the local schools one hour later than the current start time. To measure interest in the proposal, members of the team randomly select subjects attending a large high school soccer tournament played on the high school grounds on a Saturday morning. The team finds that 58% of those surveyed support a later high school start time. Which type of bias is most likely to be present in the survey results?
This is undercoverage bias because adults with older children are more likely to be included in the sample.
This is question wording bias because the phrasing of the later start times question may be confusing to some subjects.
This is nonresponse bias because some of those selected may choose to not provide their opinion on later start times.
This is voluntary response bias because vocal supporters of later start times will be more likely to offer their opinion.
Mathematics
1 answer:
almond37 [142]1 year ago
6 0

The type of bias which is most likely to be present in the survey results is undercoverage bias because adults with older children are more likely to be included in the sample.

<h3>Research</h3>

This is a diligent inquiry or examination to seek or revise facts, principles, theories,or applications. It is used to make an extensive investigation or search for truth in an experiment.

Bias

In statistics, bias is the difference between the expectation of the sample estimator and the true population value, which reduces the representativeness of the estimator by systematically distorting it

Learn more about research:

brainly.com/question/968894

#SPJ1

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The answer is 70x

Step-by-step explanation:

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3 years ago
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48 m
g100num [7]

Answer:

Answer in terms of π=144π m^3

Answer by replacing π with 3.14 is 452.16 approximately 452.2m^3

Answer to the nearest whole no. is 452m^3

Step-by-step explanation:

volume \: of \: a \: cone =  \frac{1}{3} \pi {r}^{2} h

radius =  \frac{diametre}{2}

radius = 24

height = 18

slant \: height \:  = 30

first \: step

the \: exact \: volume \: of \: the \: cone \: in \: terms \: of \: \pi

v =  \frac{1}{3} \pi {r}^{2} h

\:  \:  =  \frac{1}{3}  \times \pi \times 24 \times 18

\:  \:  \:  =  \frac{432\pi}{3}

\:  \:  \:  = 144\pi

second \: step

approximate \: answer \: using \: 3.14 \: in \: place \: of \: \pi

144 \times 3.14

= 452.16

approximately \: 452.2

last \: step

answer \: to \: the \: nearest \: whole \: number

452 {m}^{3}

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