Question

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

Answer 1

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

To find: Solution of the Equation.

Consider,

$5(b^3-2)=2(3b^3-2b^2-5)$

$5b^3-10=6b^3-4b^2-10$

$6b^3-5b^3-4b^2+10-10=0$

$b^3-4b^2=0$

$b^2(b-4)=0$

b² = 0   ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

Answer 2

Answer:

c

Step-by-step explanation: