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3 years ago

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

To find: Solution of the Equation.

Consider,

$5(b^3-2)=2(3b^3-2b^2-5)$

$5b^3-10=6b^3-4b^2-10$

$6b^3-5b^3-4b^2+10-10=0$

$b^3-4b^2=0$

$b^2(b-4)=0$

b² = 0 ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

kondaur [170]3 years ago

4 0

Answer:

Step-by-step explanation:

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I need help finding our the perimeter

barxatty [35]

Answer:

11x + 10y - 2w

Step-by-step explanation:

Hello!

To solve for the perimeter, we add up the like terms.

What are like terms?

Like terms are terms with the same variable and degree. 4x and 5y are NOT like terms because the variable is not the same. However, 4x and 3x are like terms, as adding them gives us 7x.

4x and 4x² are not like terms, because the degree of 4x is 1 (degree means the largest exponent), but the degree of 4x² is 2.

Solve for Perimeter:

Combine the like terms by adding them up.

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P = 8x - 4w + 3y + 2w + 3x + 7y
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2 years ago

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Step2247 [10]

Two and a half hours.

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3 years ago

What the answer to this equation be?

scoray [572]

If you expand the square, you have

$\dfrac{1}{4}x^2-3x=7x+8-10x$

Simplify the right hand side:

$\dfrac{1}{4}x^2-3x=-3x+8$

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3 years ago

Use the formula you just learned to help you complete the following. A circle’s diameter is approximately 14 cm.

damaskus [11]

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2 years ago

WORTH 20 POINTS HELP

vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}$

$RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}$

$ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}$

$TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}$

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$QR = \frac{9 + 1}{2 + 3} = \frac{10}3$

$RS = \frac{5-9}{-4 - 2} = \frac{2}3$

$ST = \frac{5+5}{-4 + 7} = \frac{10}3$

$TQ = \frac{-5+1}{-7 + 1} = \frac{2}3$

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram