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3 years ago

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

To find: Solution of the Equation.

Consider,

$5(b^3-2)=2(3b^3-2b^2-5)$

$5b^3-10=6b^3-4b^2-10$

$6b^3-5b^3-4b^2+10-10=0$

$b^3-4b^2=0$

$b^2(b-4)=0$

b² = 0 ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

kondaur [170]3 years ago

4 0

Answer:

Step-by-step explanation:

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What does standard deviation mean?

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3 years ago

Find the mean median mode and range for the following data 77 60 59 70 89 95

Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

77,60,59,70,89,95

Sort:

59,60,70,77,89,95

To find:

Mean
Median
Mode
Range

Mean:

$\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}$

Sum of all data divides by amount.

$\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}$

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in middle:

$\displaystyle \large{\dfrac{x_1+x_2}{2}}$

From 59,60,70,77,89,95, since 70 and 77 are in middle:

$\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}$

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

$\displaystyle \large{x_{max}-x_{min}}$ or highest value - lowest value

Thus:

$\displaystyle \large{95-59 = 36}$

Therefore, range = 36

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2 years ago