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dimulka [17.4K]
2 years ago
7

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

Mathematics
2 answers:
irinina [24]2 years ago
7 0

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

To find: Solution of the Equation.

Consider,

5(b^3-2)=2(3b^3-2b^2-5)

5b^3-10=6b^3-4b^2-10

6b^3-5b^3-4b^2+10-10=0

b^3-4b^2=0

b^2(b-4)=0

b² = 0   ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

kondaur [170]2 years ago
4 0

Answer:

c

Step-by-step explanation:

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Answer:

OD = 9.375"

Step-by-step explanation:

We can draw a line from O to B to create a triangle.

Then, Triangle ODB and Triangle ACB are similar, so their corresponding side's ratio are similar as well.

Triangle ACB, we can use pythagorean theorem to figure out CB:

AC^2 + CB^2 = AB^2

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225 + CB^2 = 289

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Now relating the corresponding sides, we can figure out OD:

\frac{OD}{DB}=\frac{AC}{CB}\\\frac{OD}{8-3}=\frac{15}{8}\\\frac{OD}{5}=\frac{15}{8}\\8OD=5*15\\OD=\frac{5*15}{8}\\OD=9.375

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