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dimulka [17.4K]
2 years ago
7

What is the solution for the equation 5/3b^3-2b-5=2/b3-2

Mathematics
2 answers:
irinina [24]2 years ago
7 0

Answer:

Option C is correct.

Step-by-step explanation:

Given Equation:

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

To find: Solution of the Equation.

Consider,

5(b^3-2)=2(3b^3-2b^2-5)

5b^3-10=6b^3-4b^2-10

6b^3-5b^3-4b^2+10-10=0

b^3-4b^2=0

b^2(b-4)=0

b² = 0   ⇒ b = 0

b - 4 = 0 ⇒ b = 4

Therefore, Option C is correct.

kondaur [170]2 years ago
4 0

Answer:

c

Step-by-step explanation:

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We are given

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r3=(fourth term)/(third term)

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we can see that all four ratios are same

r_1=r_2=r_3=r_4=2

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Calculation of general term:

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now, we can use formula

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we can plug values

and we get

a_n=2(2)^{n-1}

a_n=2^1(2)^{n-1}

a_n=(2)^{n-1+1}

a_n=(2)^{n}..................Answer


5 0
2 years ago
The width of a rectangle is 7 less than the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the re
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2 years ago
Read 2 more answers
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Semmy [17]

Answer:

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Step-by-step explanation:

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