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zysi [14]
2 years ago
5

Find the product of (4x − 3)(2x2 − 7x 1). 8x3 − 22x2 17x− 3 8x3 8x2 4x − 3 8x3 − 34x2 25x − 3 8x3 − 42x2 25x − 3.

Mathematics
1 answer:
Andrej [43]2 years ago
3 0

Product of two polynomials can be done by distribution of multiplication over addition. The product of  (4x -3)(2x^2 -7x + 1) is 8x^3 - 34x^2 + 25x - 3

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

a(b + c) = a\times b + a\times c

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

The product result of the given expression is obtained as:

(4x -3)(2x^2 -7x + 1) = 4x(2x^2 - 7x + 1) -3(2x^2 - 7x + 1)\\(4x -3)(2x^2 -7x + 1) = 8x^{1 + 2} - 28x^2 + 4x - 6x^2 + 21x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 + (-28-6)x^2 + (4 + 21)x - 3\\(4x -3)(2x^2 -7x + 1) = 8x^3 - 34x^2 + 25x - 3

Thus,

The product of  (4x -3)(2x^2 -7x + 1) is 8x^3 - 34x^2 + 25x - 3

Learn more about polynomial product here;

brainly.com/question/9106484

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Step-by-step explanation:

1 mole of any substance = 6.022 * 10²³ molecules.

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6 0
2 years ago
Find the value of 83 - [59 - (22 - 18)]
Kipish [7]
Use order of operations (PEMDAS) 
<span>83-<span>(<span>59-<span>(<span>22-18</span>)</span></span>)
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Final answer: 28 
8 0
3 years ago
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The base of a solid is the region enclosed by the graphs of y=e^x, y=0, x=0, and x = 1. If each cross-section perpendicular to t
yanalaym [24]

Answer:

A

Step-by-step explanation:

The base of a solid in the region enclosed by the graphs of <em>y</em> = eˣ, <em>y</em> = 0, <em>x </em>= 0, and <em>x</em> = 1. Each cross-section perpendicular to the <em>x</em>-axis is an equilateral triangle. We want to find the volume of the solid.

Please refer to the graph below. We are concerned with the red region.

In order to find the volume, we essentially sum up the area of the figure at each <em>x</em> value. So, we integrate from <em>x </em> = 0 to <em>x </em>= 1.

The area for an equilateral triangle is given by:

\displaystyle A=\frac{\sqrt{3}}{4}s^2

Where <em>s</em> is the side length of the triangle.

Since the triangle lies perpendicular on the region, the side length of the triangle at <em>x</em> is simply <em>y</em>, which is eˣ.

Therefore, our volume is:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(y)^2\, dx

Substitute:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(e^x)^2\, dx

Evaluate the integral. Simplify:

\displaystyle V=\frac{\sqrt3}{4}\int_0^1e^{2x}\, dx

Integrate using u-substitution:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2x}\Big|_0^1\right)

Evaluate:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2(1)}-e^{2(0)} \right)

Therefore, the volume of the solid is:

\displaystyle V=\frac{\sqrt3}{8}\left(e^2-1\right)

Our answer is A.

3 0
2 years ago
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I’m pretty sure yes it is
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