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Fittoniya [83]
3 years ago
15

Need the answer for this angle measures A? B (4x-16) C (5x+7)

Mathematics
1 answer:
marta [7]3 years ago
6 0
Is it an isosceles triangle
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Jack has some marbles. He has ten more red marbles than blue marbles. He has fewer yellow marbles than blue marbles.
kap26 [50]

Answer:

<u>Jack has at least 15 marbles: 12 red, 2 blue and 1 yellow.</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the problem correctly:

Number of red marbles = 10 more than blue marbles

Number of yellow marbles fewer than blue marbles

2. How many of each color marble could Jack have?

r = Number of red marbles

b = Number of blue marbles

y = Number of yellow marbles

r = b + 10

y < b

If y = 1, then b ≥ 2, and r = b + 10,

fulfilling the three conditions, we have:

<u>y = 1, b = 2, and r = 12</u>

5 0
3 years ago
In 2 years i will be twice as old as i was 20 years ago how old am I?
Vsevolod [243]
You are going to be 40 years old.
Twice = 2
2 times 20 is 40.
7 0
3 years ago
Read 2 more answers
MOre geometry.<br> Sorry i struggle.
il63 [147K]

1/2 (Base x height) = area

1/2 (4*x)=10

2x=10

X=5

The height is 5 units

5 0
3 years ago
Subtract. Write your answer in simplest form.<br><br> 6 3/4 - 2 3/20<br><br> I need a mixed number
umka21 [38]

Answer:

4 3/5

Step-by-step explanation:

6 3/4-2 3/20=x

3/4=15/20

15/20-3/20=12/20=6/10=3/5

6-3=3+3/5=4 3/5

6 0
2 years ago
Read 2 more answers
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
3 years ago
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