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2 years ago

How do i the find the slope?

Mathematics

1 answer:

inna [77]2 years ago

3 0

Step-by-step explanation:

$x ^{1} = - 5 \\ y ^{1} = - 2 \\ x {}^{2} = - 2 \\ y {}^{2} = 1 \\ then \: you \: solve \: with \: that \: formula \: you \: know$

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At home, 2 out of 5 people have access to board and technology. what percent is this?

Paha777 [63]

Answer:

0.4

Step-by-step explanation:

you just have to divide

2÷5=0.4

5 0

3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago

HELP PLEASE!!

Ostrovityanka [42]

Less would be the answer for both i think :P im late XD

5 0

3 years ago

Estimate the sum of numbers 9488 and 857 to the nearest 10 <br><br>Ans: ?

UNO [17]

For the first one it’s 9490 & for the second it’s 860

5 0

3 years ago

All I need to know is how to do 13. After I know how to do 13, I'll know how to do the rest. Please show your work and explain i

s2008m [1.1K]

MK is the same as NL.
Just read the rest of the questions.
They practically give you the answers.

7 0

3 years ago