2^6 (or two to the sixth power) is equal to 4^3, which equals out to 64.
Because y varies inversely as x, instead of directly, you will need to multiply x by a fractional number (or divide x) in order to find y.
When x=8, y=4. Therefore, to find y, you need the "equation" y=(1/2)(x) or y=x/2.
So, when x=2, y=(1/2)(2) or y=2/2.
And so, y=1
Hope this helps!
Answer:
the answer I got was x>36
I hope this helped
2/3 x 15 = 10
1/5 x 200 = 40
Your Final Answer: 40 - 10 = 30
Answer:
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
Step-by-step explanation:
Let us consider the image attached.
Center of circle be O.
Arc AB subtends the angle
on the circle and
on the center of the circle.
To prove:

Proof:
In
: AO and PO are radius of the circles so AO = PO
And angles opposite to equal sides of a triangle are also equal in a triangle.
So, 
Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

Similarly,
In
: BO and PO are radius of the circles so BO = PO
And angles opposite to equal sides of a triangle are also equal in a triangle.
So, 
Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

Now, we can see that:

Using equations (1) and (2):

Hence, proved.