<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
The estimated answer would be 480.81
By definition, a polynomial is an expression with more than one term. That is a monomial. We have names for 2-termed polynomials (binomials) and 3-termed polynomials (trinomials), but that's where the naming stops and they all are called polynomials after that. Our degree is the same as the highest exponent. So our degree is a fifth degree. The leading coefficient is the number that starts out the whole polynomial AS LONG AS IT IS IN STANDARD FORM. If our polynomial started with the -4x^4, our leading coefficient would NOT be -4 since the highest degree'd term will always come first in standard form. Your choice for your answer is the first one given. Degree: 5 Leading Coefficient: -13.
Answer:
180-140=50 180-90-50= 40 m=40
