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3 years ago

I need help Brainiest

Mathematics

1 answer:

nekit [7.7K]3 years ago

8 0

Answer: The answer is A

Step-by-step explanation: Looking at the graph we can see that if we add up row 1, we get 0.75 of his friends go to the movies, while 0.69 go to soccer games.

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What is (x+y+2)(y+1)<br> a y^2+4xy+2<br> b xy+4y+x+2<br> c y+x+y+2<br> d y^2+xy+x3y+2

mina [271]

The answer is A.y^2+4xy+2

7 0

3 years ago

A number when divided by 5 gives 0 as remainder, that number when divided by 7 gives 0 as remainder also. What will be the remai

victus00 [196]

Answer:

zero

Step-by-step explanation:

The computation of the remainder when the number would be divided by 35

Let the number be x

So if x is divided by 5 gives the remainder 0

x = 0

And, if x is divided by 7 gives the remainder 0

x = 0

So if x is divided by 35 so the remainder is also zero

7 0

3 years ago

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

Dana has 8 baseball cards, 10 football cards, 4 hockey cards, and 14 basketball cards. All the cards are the same size and shape

nalin [4]

Answer:1/8

Step-by-step explanation:

well the total amount you have of cards is 36 so you will have 4/36 now you just need to reduce and you will get 1/8

6 0

3 years ago

Write the equation of the line parallel to 3x-y=7 that passes through point (-5, -3)

IceJOKER [234]

<h2>Answer:</h2>

$\boxed{y=3x+12}$

<h2>Step-by-step explanation:</h2>

In this problem we know the equation of a line, which is:

$3x-y=7$

We also can write this equation as:

$y=3x-7$

This line has a slope $m=3$ which is also the slope of the line we are looking for because they're parallel. We also have a point $(-5,-3)$ . Therefore, we can write this equation as follows:

$y-y_{0}=m(x-x_{0}) \\ \\ y-(-3)=3(x-(-5)) \\ \\ y+3=3(x+5) \\ \\ y+3=3x+15 \\ \\ \boxed{y=3x+12}$

From the figures below, the line in red is $3x-y=7$ while the line in blue is $y=3x+12$ and this line passes through the point (-5, -3)!

4 0

3 years ago

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