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DanielleElmas [232]
3 years ago
10

Add:

Mathematics
2 answers:
True [87]3 years ago
8 0

Answer:

1. -195

2.-771

3. 2

1. 9

2.-3

3. -10

4. 205

Step-by-step explanation:

Sergio [31]3 years ago
4 0

Answer:

<h3>Add:</h3>

1. 258 and -453

=258 -453

= -195

2.-528 and -243

= -528 + (-243)

= -538 -243

= - (528+243)

= -771

3.-13 and 15

= -13 + 15

= 2

<h3>Subtract:</h3>

1. -3 from 12

= 12 - (-3)

= 12+3

=15

2. 4 from -7

= 4 - (-7)

= 4+7

= -11

3. -8 from -2

= -8 - (-2)

= -8+2

= 6

4.329 from -124

= 329 - (-124)

= 329 + 124

= -453

Step-by-step explanation:

<h3><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u>s</u></em><em><u>!</u></em></h3>
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Hey, I need help with questions 1 and 2, if anyone can help, please? thanks!
Eva8 [605]

The correct works are:

  • Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3.
  • \frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

Blue(s + h) = 2(s + h)^2 + 3

Evaluate the exponent

Blue(s + h) = 2(s^2 + 2sh + h^2) + 3

Expand the bracket

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

Evaluate the like terms

\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

brainly.com/question/13136492

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