<span>(a) $7.04
(b) 704/1599
(c) 0.44
(d) 14
(e) $98.56
(a) How much profit does Lucy earn when she sells a necklace?
Since the problem states that her profit is the sale price minus the cost of materials and labor, we have the following equation.
P = $15.99 - $3.38 - $5.57
P = $12.61 - $5.57
P = $7.04
So her profit is $7.04 per necklace.
(b) Write a fraction of the profit per sale price of the necklace. Record your answer as a fraction using whole numbers.
The raw fraction is 7.04/15.99, to get rid of the decimal point, multiply top and bottom by 100, getting 704/1599.
The prime factors of 704 are 2,2,2,2,2,2,11 and the prime factors of 1599 are 3,13,41. Since neither 704, nor 1599 share any common factors, the fraction can't be reduced and the final answer is 704/1599.
(c) What decimal of every dollar of the sale price of the necklace is profit using the fraction from Part (b)?
Pardon the lack of formatting
704/1599 = 0.4403
Rounded to the nearest hundredth gives 0.44
(d) Lucy collected $223.86 selling necklaces at a craft fair. How many necklaces did Lucy sell? Show your work.
This question is asking for total cost. So divide the $223.86 by the sale price of $15.99.
$223.86 / $15.99 = 14
14 necklaces were sold.
(e) How much profit did she earn from the number of necklaces she sold? Show your work.
Since we know from (a) that she has $7.04 profit per necklace, just multiply the amount of profit by the number sold. So
$7.04 * 14 = $98.56</span>
Answer:
19
Step-by-step explanation:
20/4 + 13
20/4 = 6
6+13 = 19
We are asked in this problem to find the real root of the polynomial f(x) = x3 + 0.5x2 + 4.5. in this case, to find the root of the equation, we equate the equation to zero.
<span>f(x) = x³ + 0.5x² + 4.5 = 0
2x3 + x^2 + 9 = 0
</span><span>x1=−1.83557
</span>x2=0.66779+1.41619∗i
x3=0.66779−1.41619∗i
answer is -1.84
Question
Marcus asked 10 people at a juggling festival what age they were when they started to juggle. Which interval contains the median age?
Answer:
See Explanation
Step-by-step explanation:
Given
Required
The median interval
The question is incomplete, as the required data is not given.
To solve this question, I will use the following assumed dataset.
First, calculate the median position.
This implies that the median is the mean of the 5th and 6th data
So, we have the interval to be.
![Median = [5th, 6th]](https://tex.z-dn.net/?f=Median%20%3D%20%5B5th%2C%206th%5D)
![Median=[21,22]](https://tex.z-dn.net/?f=Median%3D%5B21%2C22%5D)
<em>Generally, the median of 10 data set is located at interval 5 to 6</em>
Answer:
4
Step-by-step explanation:
