What is the probability that the first player does not get a blue character?

Mathematics

1 answer:

Yanka [14]3 years ago

3 0

If there are 14 different scenarios that can happen (Blue 1-5, Green 1-6, Red 1-3), and 9 of them are not blue, there is a 9/14 chance that the first pick is not blue. to get percentages, you divide 9 by 14 to get 0.64, or 64 percent chance at not picking blue.

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In the diagram, point D divides line segment AB in the ratio of 5:3. If line segment AC is vertical and line segment CD is horiz

BabaBlast [244]

Answer:

C (2, -1)

Step-by-step explanation:

C has the same x coordinate as A = 2

that eliminates A and B.

and the y value of C has to be closer to the y value of B than to the y value of A (due to the 5:3 ratio).

so, without spending unnecessary effort on actual calculation, we can directly derive the correct answer to be C.

but to show in numbers, the "coordinate triangle" of the difference between D and B is a similar triangle to ACD. and so, the ratio of one side pair applies then to all other sides too. including the individual coordinate differences.

so, also the y difference of A to D relates to the y difference between D and B in the same ratio of 5:3 of the overall y difference of A to B.

the y difference A to B is 2 - -6 = 8

the 5/3 split of 8 units is actually 5 and 3.

so, the y coordinate of D is -6 + 5 = -1

and C must have the same y coordinate.

therefore, it is proven that answer C (2, -1) is the right answer.

4 0

3 years ago

I can't figure it out

Strike441 [17]

Answer:

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