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Katarina [22]
4 years ago
11

What equation can I use to find the side of a cube whose area is 729?

Mathematics
1 answer:
Tom [10]4 years ago
8 0
#1 There is no area of a cube. There is only a volume.
#2 The formula is V = s^{3} where s is the side.

Substitute 729 in V since that is the volume.
729 = s^{3}

Take the cube root and you will get 9.

So the formula is V = s^{3} and the side is 9. 
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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
Please help will give brainliest please
lyudmila [28]

Answer:

20

Step-by-step explanation:

10 is equal to the side infront of it. 10 +10 = 20

rounding it to the nearest degree will also be 20

8 0
3 years ago
Ok ok, Jonathan is making his favorite pasta dish. His mom ate 2/7 of the pasta, and his brother ate 1/6 of the pasta. How much
givi [52]

Answer:

It is 0.4524 rounded simply you can say 0.45

Step-by-step explanation:

if you multiply 2/7 by 6 which is 12/42 and 1/6 times 7 which is 7/42 and add both fractions you will get 19/42 which is 0.45 you can either say the answer is 0.45 or 19/42.

8 0
3 years ago
Read 2 more answers
Mr. Tragrr has $500.00 to spend at a bicycle store. All the prices listed down below include tax.
fgiga [73]

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.

Spent so far:

... 273.98 + 3×7.23 +42.36 = 338.03

Remaining available funds:

... 500.00 -338.03 = 161.97

The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.

Mr. Traeger can buy two (2) cycling outfits with the remaining money.

_____

The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.

8 0
3 years ago
Read 2 more answers
The difference of the range and the interquartile range of the data set represented by the box plot is .
Ivahew [28]
When presented with a box plot, it is better to identify the 5 numbers that are important in the box plot.

5 number summary of the boxplot.
1) minimum number - 16
2) 1st quartile - 21
3) 2nd quartile or median - 26
4) 3rd quartile - 29
5) maximum number - 34

Range is the difference of the maximum value from the minimum value of the data set.
Interquartile range is the difference of the 3rd quartile from the 1st quartile.

Range: 34 - 16 = 18
IQR: 29 - 21 = 7


6 0
4 years ago
Read 2 more answers
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