$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

3 0

3 years ago

Help plz I’ll give brainliest and I’m struggling with this problem

hodyreva [135]

The line is starting from right side and goes thorough left .

Means

Its starts from 1st Quadrant and goes to 3rd Quadrant.(+ve to -ve)
Y is infinite

Hence

The solution is

$\\ \sf\longmapsto (0,\infty]$

6 0

3 years ago

Please Help, work this out if you want brainliest answer (80 points). Jimmy and John are trying to put a mixture together of blu

Scorpion4ik [409]

Hello Jsurginer2000otz2ik, <span>it would be reasonable to say that the mixture could contain 6 ounces of blue jelly beans and 4 ounces of red jelly beans because they want a price of $ 3.08 per bag, so $ 0.27*6=1.62 and $ 0.44 * 4 ounces = 1.76. add them and it comes out to $ 3.38 which is equivalent to 3.08 but if its not the answer your looking for just say so i can correct myself.</span>
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4 0

4 years ago