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Zolol [24]
3 years ago
15

Which ordered pairs make the inequality true?

Mathematics
1 answer:
salantis [7]3 years ago
7 0
1.
(-2,3) \\
x=-2 \\
y=3 \\ \Downarrow \\
-2+3 \times 3

The ordered pairs (-2,3) and (5,1) make the inequality true.

2.
15y-3(4y+10)=15y-3 \times 4y-3 \times 10= 15y-12y-30= \\
=3y-30

The simplified form of the expression is 3y-30.
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I don’t understand these
BaLLatris [955]
So these are basically isolating the variables.
The first equation is 3g + 5 =17.
In order to isolate the variable, we would have to get g by itself, that means 5 would have to go. In order to do this, we would do the opposite. Since it is positive 5 we would add negative 5, in order for it to disappear. This works because a positive 5 and negative 5 cancel each other out. Whatever you do to one side of the equation you have to do to the other, since we subtract 5 on one side we have to subtract 5 on the other. Therefore we would do 17-5.
Now we have 3g=12
We know that 3g is basically 3 multiplied by g. The opposite of multiplication is division.Therefore we would divide by 3 on both sides.
The answer to the first question would be g= 4.
And if you want to check if your answer is correct you plug the value in.
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5 0
3 years ago
Which expression has the same value as the one below?
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Answer:

answer is B 38-18

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38 + (-18)

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