Which ordered pairs make the inequality true?

1 answer:

7 0

1.
$(-2,3) \\
x=-2 \\
y=3 \\ \Downarrow \\
-2+3 \times 3$

The ordered pairs (-2,3) and (5,1) make the inequality true.

2.
$15y-3(4y+10)=15y-3 \times 4y-3 \times 10= 15y-12y-30= \\
=3y-30$

The simplified form of the expression is 3y-30.

You might be interested in

Can someone please take the time out of their day and help me with this question

ruslelena [56]

Answer:

76, 76 104

Step-by-step explanation:

Angle 3 is vertical so it is congruent to Angle 2.

Angle 6 is corresponding, so it is congruent to Angle 2.

Angle 8 is linear to Angle 6, so they add to 180

5 0

3 years ago

Read 2 more answers

If the value of 2x 3 is 2, then what is the value of x?

lina2011 [118]

I think it is -.5 for x

3 0

3 years ago

The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2

Darina [25.2K]

Answer:

a) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 0$ are $x_{1}\approx -0.25$ and $x_{2} \approx 1.25$ .

b) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 2$ are $x_{1}\approx -0.5$ and $x_{2} \approx 1.5$

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial $y = 4\cdot x^{2}-4\cdot x -1$ , where $x$ is related to the horizontal axis of the Cartesian plane, whereas $y$ is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case: