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e-lub [12.9K]
4 years ago
7

Help me with this math problem

Mathematics
2 answers:
allochka39001 [22]4 years ago
6 0

D is the answer also what you can do when u need to solve a question mark out the ones than can’t be the answer and find the close one to the answer

jek_recluse [69]4 years ago
4 0

Answer:

15.49

Step-by-step explanation:

visually picture the diagram, the adjacent side of triangle will be equals to 7.6ft, the height will be 13.5, we use Pythagorean theorem, 7.6^2 + 13.5^2 = x^2

solve, for x by square rooting x which will give 15.49

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If line T is a transversal of lines I and m, name the angel relationship of the given angle pairs
kolbaska11 [484]

Answer:

  a. corresponding angles (congruent)

  b. alternate exterior angles (congruent)

  c. same-side interior angles (supplementary)

Step-by-step explanation:

The vocabulary associated with angles created by a transversal and parallel lines is not so difficult.

If angles are on the same side of the transversal, they are <em>same-side</em> angles. If not, they are <em>alternate</em> angles.

If angles are between the parallel lines, they are <em>interior</em> angles. If not, they are <em>exterior</em> angles.

If the angles are in the same direction from the point of intersection of the transversal with the parallel line, they are <em>corresponding</em>. Corresponding angles are same-side; one is interior and the other is exterior.

These names generally apply to angles with different vertices.

__

a. Both angles are northwest of the intersection point; they are same-side, and one is interior and one is exterior. They are corresponding angles. (congruent)

__

b. The angles are on opposite sides of the transversal and are outside the parallel lines. They are alternate exterior angles. (congruent)

__

c. The angles are on the same side of the transversal, and both are between the parallel lines. The are same-side interior angles. (supplementary)

3 0
3 years ago
Calculate the percentage increase for the price of a book increasing from 250 to 275.50​
Naddika [18.5K]

Step-by-step explanation:

increase in price=275.50-250

=75 .50

now,in precent

( increase in price÷initial price )×100%

=(75.50÷250) ×100%

= 30.2%

6 0
3 years ago
Read 2 more answers
Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t
Yanka [14]

Answer:

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

\hat p=\frac{X}{n} estimated proportion of  scissors selected for each friend

p_o=\frac{1}{3}=0.333 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:  

Null hypothesis:p\geq 0.333  

Alternative hypothesis:p < 0.333  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

6 0
4 years ago
Which statements are true about the linear inequality y &gt; 3/4x – 2? Check all that apply.
Gemiola [76]
Check the picture below.

5 0
4 years ago
Subtract: 1/3 - 5/6? *<br>​
Marianna [84]

Answer:

mmmmmm heyyyyyyyyyyyyy

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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